我得到了两个index.php并且都使用了一个bootstrap.php。引导文件正在设置一个DI-Container，我需要在两个索引文件访问这个DI-Container。
首先，我正在考虑使用一个简单的return在bootstrap.php:
bootstrap.php
<?php
require __DIR__ . '/vendor/autoload.php';
$container = new League'Container'Container;
// add some services
return $container;
index . php
<?php
$container = require __DIR__ . '/bootstrap.php';
$container->get('application')->run();
我在某处读到像这样使用返回语句是一个坏习惯。所以我想知道如何使容器在index.php访问在一个简单和适当的方式?
不需要返回，如果包含了该文件，则已经可以访问变量$container
bootstrap.php
<?php
require __DIR__ . '/vendor/autoload.php';
$container = new League'Container'Container;
// add some services
index . php
<?php
require __DIR__ . '/bootstrap.php';
$container->get('application')->run();
更新(跟随注释):
bootstrap.php
<?php
require __DIR__ . '/vendor/autoload.php';
// add some services
return new League'Container'Container;
index . php
<?php
$container = require __DIR__ . '/bootstrap.php';
$container->get('application')->run();
另一个例子:
如果您需要在返回之前在容器对象上添加服务，如果您希望避免使用全局变量，则可以使用静态helper类(仅举个例子):
class Context {
private static $container = null;
public static function getContainer() {
return self::$container;
}
/* maybe you want to use some type hinting for the variable $containerObject */
public static function setContainer( $containerObject ) {
self::$container = $containerObject;
}
}
bootstrap.php
<?php
require __DIR__ . '/vendor/autoload.php';
// require the Context class, or better get it with your autoloader
Context::setContainer( new League'Container'Container );
// add some services
Context::getContainer()->addMyService();
Context::getContainer()->addAnotherService();
//if you want to, you can return just the container, but you have it in your Context class, so you don't need to
//return Context::getContainer();
index . php
<?php
require __DIR__ . '/bootstrap.php';
Context::getContainer()->get('application')->run();