CakePHP 3.X选择嵌套实体的表单 - CakePHP 3.x select form for nested entities

CakePHP 3.x select form for nested entities

尝试为嵌套实体数组创建表单选择输入。我已经用这种方式"手动"完成了它，但它感觉不是很硬。

<select name="restaurant_id" class="form-control" id="restauarnt-id">
  <option value="">Select Restaurant</option>
  <?php foreach($post->city->restaurants as $restauarnt): ?>
    <option value="<?= $restauarnt->id?>"><?= $restauarnt->name ?></option>
  <?php endforeach; ?>
</select>

像这样的东西感觉更合适:

$this->Form->input('restauarnt_id', ['options' => $post->city->restaurants, 'empty' => 'Select Restaurant', 'class' => 'form-control', 'label' => false]);

但是这给了我:

<select name="restauarnt_id" class="form-control" id="restauarnt-id">    
    <option value="">Select Restaurant</option>
    <option value="0">{"id": 1, "city_id": 1, "name": "Some Place"}</option>
</select>

最好的方法是什么?

(Cake Version 3.x)

控制器:

$restaurants = $this->[(whatever $post is)]->Cities->Restaurants->find('list'
    'keyField' => 'id',
    'valueField' => 'name'
);
$this->set(compact('restaurants'));

在视图:

<?= $this->Form->input('retaurant_id', [
    'empty' => '--',
    'label' => 'Restaurants'
    ]); ?>

在控制器添加:

$restaurants = $this->Restaurants->find('list');
$this->set(compact('restaurants'));

<<p> 视图/strong>
<?= $this->Form->input('restauarnt_id', ['type' => 'select', 'options' => $restaurants, 'empty' => __('Select Restaurant'), 'label' => false]) ?>