php延迟静态绑定检查错误期望T_FUNCTION - php late static binding revieve error expecting T_FUNCTION

php late static binding revieve error expecting T_FUNCTION

我是OOP的新手，我一直在这个例子上工作，但我似乎无法摆脱这个错误

Parse error: syntax error, unexpected ';', expecting T_FUNCTION in C:'Program Files (x86)'Apache Software Foundation'Apache2.2'...'php_late_static_bindings.php on line 16

我试图执行以下代码:

abstract class father {
    protected $lastname="";
    protected $gender="";
    function __construct($sLastName){
        $this->lastname = $sLastName;
    }
    abstract function getFullName();
    public static function create($sFirstName,$sLastName){
        return new self($sFirstName,$sLastName);
    };
}
class boy extends father{
    protected $firstname="";
    function __construct($sFirstName,$sLastName){
        parent::__construct($sLastName);
        $this->firstname = $sFirstName;
    }
    function getFullName(){
        return("Mr. ".$this->firstname." ".$this->lastname."<br />");
    }
}
class girl extends father{
    protected $firstname="";
    function __construct($sFirstName,$sLastName){
        parent::__construct($sLastName);
        $this->firstname = $sFirstName;
    }
    function getFullName(){
        return("Ms. ".$this->firstname." ".$this->lastname."<br />");
    }
}

$oBoy = boy::create("John", "Doe");
print($oBoy->getFullName());

有人有什么想法吗?$ girl = girl::create("Jane"， "Doe");打印($ oGirl -> getFullName ());

首先要去掉方法定义后面的分号:

public static function create($sFirstName,$sLastName){
    return new self($sFirstName,$sLastName);
} // there was a semi-colon, here

然后，您可能想使用static，而不是self ，这里:

public static function create($sFirstName,$sLastName){
    return new static($sFirstName,$sLastName);
}

解释:

self指向编写它的类——这里是father类，它是抽象的，不能被实例化。另一方面，
static意味着晚期静态绑定——并且，在这里，将指向您的boy类;这是你想实例化的对象。

PHP的错误报告通常很好。读一下错误。问题在这里:

public static function create($sFirstName,$sLastName){
    return new self($sFirstName,$sLastName);
};

去掉训练分号。

public static function create($sFirstName,$sLastName){
    return new self($sFirstName,$sLastName);
}