我无法检查数据库中是否存在一行,如果不显示消息。代码如下。我需要一点帮助。
<?php
$result = mysqli_query($mysqli, "SELECT client_cv FROM formular_client WHERE id = '$id'");
if (mysqli_num_rows($result) > 0){
echo "<a href='../cv/" . $rows['client_cv'] . "' target='_blank' class='btn btn-lg btn-primary'><span class='glyphicon glyphicon-download-alt'></span> Descarca CV</a>";
} else {
echo "<a href='#' target='_blank' class='btn btn-lg btn-primary'><span class='glyphicon glyphicon-download-alt'></span> Fara CV</a>";
}
?>
如果您想根据client_cv
是否有值来显示不同的链接,请尝试此
<?php
$result = mysqli_query($mysqli, "SELECT client_cv FROM formular_client WHERE id = '$id'");
if (mysqli_num_rows($result) > 0){
$rows = mysqli_fetch_array($result);
if (strlen($rows["client_cv"]) > 0){
echo "<a href='../cv/" . $rows['client_cv'] . "' target='_blank' class='btn btn-lg btn-primary'><span class='glyphicon glyphicon-download-alt'></span> Descarca CV</a>";
} else {
echo "<a href='#' target='_blank' class='btn btn-lg btn-primary'><span class='glyphicon glyphicon-download-alt'></span> Fara CV</a>";
}
} else {
echo "No record found"
}
?>