我有2个php文件，一个是"Db_function.php"answers"index.php"， "index.php"将在"Db_function.php"中进行函数调用。我想通过ajax调用"index。php"这是我的代码
Html文件
<Html>
<body>
<script type="text/javascript" src="js/index.js"></script>
<input type="button" value="Get" onclick="get()">
</body>
</html>
Js文件
function get() {
$.ajax({ url: 'index.php',
data: {tag:'get_backup', email:'mail@mail.com', password:'123'},
type: 'post',
datatype:'json'
success: function(output) {
alert(output);
}
});
}
index . php
/*with connect value*/
if ($tag == 'get_backup'){
// store user
$email = $_POST['email'];
$password = $_POST['password'];
$user = $db->get_backup($email, $password);
Db_funtion.php
public function get_backup($email, $password) {
$result = mysql_query("SELECT * FROM users WHERE email = '$email'") or die(mysql_error());
// check for result
$no_of_rows = mysql_num_rows($result);
if ($no_of_rows > 0) {
$result = mysql_fetch_array($result);
$salt = $result['salt'];
$encrypted_password = $result['encrypted_password'];
$hash = $this->checkhashSSHA($salt, $password);
// check for password equality
if ($encrypted_password == $hash) {
// user authentication details are correct
$response = array();
$result2 = mysql_query("SELECT * FROM contact_store WHERE (email ='$email' AND backup_name='$email')") or die(mysql_error());
if (mysql_num_rows($result2) > 0) {
// looping through all results
// contact_stores node
$response["contact_stores"] = array();
while ($row = mysql_fetch_array($result2)) {
// temp user array
$contact_store = array();
$contact_store["backup_name"] = $row["backup_name"];
$contact_store["email"] = $row["email"];
$contact_store["data"] = $row["data"];
// push single contact_store into final response array
array_push($response["contact_stores"], $contact_store);
}
// success
$response["success"] = 1;
// echoing JSON response
echo json_encode($response);
} else {
// no contact_stores found
$response["success"] = 0;
$response["message"] = "No contact_stores found";
// echo no users JSON
echo json_encode($response);
}
}
} else {
// user not found
return false;
}
}
Json返回如下
{"contact_stores":[{"backup_name":"nhi@gmail.com","email":"nhi@gmail.com","data":"[]"}],"success":1}
但是我的问题是当我在html文件中按下get按钮时，什么都没有发生。有什么需要帮助的吗?
您似乎没有定义您在输入元素中提供的get()函数。
试试这个HTML:
<input id="get" type="button" value="Get">
$('#get').click(function() {
$.ajax({ url: 'index.php',
data: {tag:'get_backup', email:'mail@mail.com', password:'123'},
type: 'post',
datatype:'json'
success: function(output) {
alert(output);
}
})
});