如何使用引用获得最后一个方法的输出

我有这个难题，可以通过参考文献来解决。我试图把这个&参考符号，只是无处不在，尽管无济于事。

<?php 
class main
{
    private $property = []; 
    function a()
    {
        $this->property[] = 'method: '.__METHOD__.' was called '; 
        return $this; 
    }
    function b()
    {
        $this->property[] = 'method: '.__METHOD__.' was called '; 
        return $this; 
    }
    function c()
    {
        $this->property[] = 'method: '.__METHOD__.' was called '; 
        return $this; 
    }
    function end()
    {
        var_dump($this->property);
    }
}

正如你所看到的，它是一个简单的类和它的方法，所有的方法都增加了一个类属性的值，所有的方法都返回类对象(是可链接的)，除了end()方法。

现在，为了实现我的应用程序，我必须调用类方法

$a = new main;
$a->a()->end(); 
$a->b()->end(); 
$a->c()->end(); 

现在，您可以看到的问题是，输出将是这样的。

array(1) {
  [0]=>
  string(27) "method: main::a was called "
}
array(2) {
  [0]=>
  string(27) "method: main::a was called "
  [1]=>
  string(27) "method: main::b was called "
}
array(3) {
  [0]=>
  string(27) "method: main::a was called "
  [1]=>
  string(27) "method: main::b was called "
  [2]=>
  string(27) "method: main::c was called "
}

我要找的是，只得到最后一个数组。即:

array(3) {
  [0]=>
  string(27) "method: main::a was called "
  [1]=>
  string(27) "method: main::b was called "
  [2]=>
  string(27) "method: main::c was called "
}

因为，如我前面的代码所示，我是这样调用函数的。

$a = new main;
$a->a()->end(); 
$a->b()->end(); 
$a->c()->end(); 

获取最后一个数组而不是其他两个数组是有意义的。我意识到，达到这个目的的一种方法是，启动对象三次，如

(new main)->a()->end(); 
(new main)->b()->end(); 
(new main)->c()->end(); 

但是，我希望，在中间的某个地方，使用clone或reference，可能只能得到最后一个数组。

谢谢