PHP旋转和保存不做任何事情

给这个旋转:(测试)

<?php
$path   = '/Volumes/yoda/websites/zepel.website.2013/images/blog/display';
$file   = '10.jpg';
$degrees = 90;
header('Content-type: image/jpeg');
$filename = $path . "/" .$file;
$source = imagecreatefromjpeg($filename) or notfound();
$rotate = imagerotate($source,$degrees,0);
imagejpeg($rotate);
imagedestroy($source);
imagedestroy($rotate);
?>

问题出在imagejpg函数中。应该是这样的:

header('Content-type: image/jpeg');
imagejpeg($rotate);

查看imagerotate手动链接

的问题，是你在浏览器中显示的图像和算法的另一个文本，这就是为什么你得到的"奇怪的文本"，尝试保存图像:

imagejpeg($rotate, "test.jpeg");

You can use this for rotate image
$image = 'images/me.jpg';

// Set the path to the image to rotate
$input_image = $image;
//How many degrees you wish to rotate
$degrees = 90;
// Create the canvas
            $info = getimagesize($image);
            if($info['mime']) {
                if($info['mime']=='image/gif'){
                    $canvas = imagecreatefromgif($image);
                    // Rotates the image
                    $rotate = imagerotate( $canvas, $degrees, 0 ) ;
                    // Save the image as output.jpg
                    imagegif( $rotate, $image );
                }elseif($info['mime']=='image/jpeg'){
                    $canvas = imagecreatefromjpeg($image);
                    // Rotates the image
                    $rotate = imagerotate( $canvas, $degrees, 0 ) ;
                    // Save the image as output.jpg
                    imagejpeg( $rotate, $image );
                }elseif($info['mime']=='image/png'){
                    $canvas = imagecreatefrompng($image);
                    // Rotates the image
                    $rotate = imagerotate( $canvas, $degrees, 0 ) ;
                    // Save the image as output.jpg
                    imagepng( $rotate, $image );
                }
            }
// Clear the memory of the tempory image
imagedestroy( $canvas );
?>
<img src="<?=$image?>">

这对我有用，(更改为png)如果报头数据还没有流出，你可以使用报头。如果header已经消失，使用"/> "如果您不添加时间，您的浏览器可能只显示缓存版本，而不是您刚刚更新的旋转版本。请注意，使用lastmod会导致更长的页面加载时间，特别是在图像较大的情况下，但是如果用户想要查看发生了什么，则必须使用这个。

$rotateFilename="path to file (not http)";
$degrees = 90;
if($fileType == 'jpg' || $fileType == 'jpeg'){
 // if header data has not gone out yet...  header('Content-type: image/jpeg');
$source = imagecreatefromjpeg($rotateFilename);
 // Rotate
$rotate = imagerotate($source, $degrees, 0); //do the deed
imagejpeg($rotate,$rotateFilename); //saves the file

// Free the memory
imagedestroy($source);
imagedestroy($rotate);
}