如何在字符串中搜索具有变量的子字符串，并将其替换为包含带有 PHP 的子字符串变量的内容 - How do I search for a substring with a variable within a string and replace it with content that contains the substring variable with PHP?

How do I search for a substring with a variable within a string and replace it with content that contains the substring variable with PHP?

假设我有一个字符串：

$text = "This is my string exec001 and this is the rest of the string exec222 and here is even more execSOMEWORD a very long string!"

我想用一些新文本替换字符串中出现的"exec？"，同时我想将

"exec"后面的文本存储在一个单独的变量中，以便在替换文本时可以使用它。

例如，假设我想将每次出现的 exec???替换为，

???

，因此生成的字符串为：

$text2 = "This is my string <html>001</html><div>001</div> and this is the rest of the string <html>222</html><div>222</div> and here is even more <html>SOMEWORD</html><div>SOMEWORD</div> a very long string!"

如何在 PHP 中执行此操作？

提前非常感谢。

以下是使用preg_replace的方法：

$text = "This is my string exec001 and this is the rest of the string exec222 and here is even more execSOMEWORD a very long string!";
$text2 = preg_replace('/'bexec('S+)/', "<html>$1</html><div>$1</div>", $text);
echo $text2,"'n";

这将替换所有出现的execwhatever。
'S+代表任何非空格字符。
'b是一个单词边界。

您可以在此处找到更多信息。

输出：

This is my string <html>001</html><div>001</div> and this is the rest of the string <html>222</html><div>222</div> and here is even more <html>SOMEWORD</html><div>SOMEWORD</div> a very long string!

根据评论更新

如果要替换多个字符串，只需执行以下操作：

$text2 = preg_replace('/'bexec([^:'s]+):([^:'s]+)/', "<html>$1</html><div>$2</div>", $text);

其中[^:'s]表示任何不是分号或空格的字符

     exec'S+

这个正则表达式可以替换所有执行词。请参阅演示。

http://regex101.com/r/qK1pK7/1