我如何使一个php代码弹出一个新窗口 - How can I make a php code pop up a new window?

How can I make a php code pop up a new window?

我有一个wordpress插件，允许我将人们发送到一个新的url。而不是转到同一页面的URL，让用户离开我的网站。我希望当他们访问url

时打开一个新窗口

如何编辑此代码以打开新窗口?

  <?php
    /**
  Plugin Name: [WPJB] Application URL
   Version: 1.1
  Author: Greg Winiarski
 Description: Allows to set application URL on per job basis.
*/
// Plugin activation
register_activation_hook( __FILE__, 'wpjb_aurl_register');
function wpjb_aurl_register() {
// registers new custom field in wp_wpjb_meta table
wpjb_meta_register("job", "application_url");
}
// Plugin deactivation
register_deactivation_hook( __FILE__, 'wpjb_aurl_unregister');
function wpjb_aurl_unregister() {
// do nothing ...
}
// Adding custom fields to the form
add_filter("wpjb_form_init_job", "wpjb_aurl_init_job");
add_filter("wpja_form_init_job", "wpjb_aurl_init_job");
function wpjb_aurl_init_job($form) {
// adding new fields to the form
$e = $form->create("application_url", "text");
$e->setBuiltin(false);
$e->setLabel("Application URL");
$e->addFilter(new Daq_Filter_WP_Url);
$e->addValidator(new Daq_Validate_Url);
$e->setValue($form->getObject()->meta->application_url->value());
$form->addElement($e, "company");
return $form;
}

add_action("wpjb_front_pre_render", "wpjb_aurl_pre_render", 10, 2);
 function wpjb_aurl_pre_render($app, $file) {
 global $post_type;
try {
    $c1 = is_wpjb() && wpjb_is_routed_to("index.single");
} catch(Exception $e) {
    $c1 = false;
}
$c2 = $post_type == "job";
if(!$c1 && !$c2) {
    return;
}
$job = $app->controller->view->job;
if(!$job->meta->application_url->value()) {
    return;
}
$app->controller->view->application_url = $job->meta->application_url-    >value();
}
?>

你不能完全用PHP来做，但是你可以代替重定向到新的url echo javascript，它将在加载页面时被触发，将在一个新的窗口或选项卡中打开url。

使用类似

的东西

Echo "<script> var win = window.open(".$job->meta->application_url->value().", '_blank'); win.focus();</script>";

在你的php脚本中可能在你现在的位置

$app->controller->view->application_url = $job->meta->application_url->value();