我知道.htaccess是如何工作的，我不能决定，写什么规则…
我选择了Zend框架的规则:
RewriteEngine On
# The following rule tells Apache that if the requested filename
# exists, simply serve it.
RewriteCond %{REQUEST_FILENAME} -s [OR]
RewriteCond %{REQUEST_FILENAME} -l [OR]
RewriteCond %{REQUEST_FILENAME} -d
RewriteRule ^.*$ - [NC,L]
# The following rewrites all other queries to index.php. The
# condition ensures that if you are using Apache aliases to do
# mass virtual hosting, the base path will be prepended to
# allow proper resolution of the index.php file; it will work
# in non-aliased environments as well, providing a safe, one-size
# fits all solution.
RewriteCond %{REQUEST_URI}::$1 ^(/.+)(.+)::'2$
RewriteRule ^(.*) - [E=BASE:%1]
RewriteRule ^(.*)$ %{ENV:BASE}index.php [NC,L]
所以正如它所说的，不存在的一切将被重定向到index.php，话之后我将处理请求的uri，但是关于php文件，只包含类，我保持我的业务逻辑，这是对的-用户将收到空白页，但我想知道如何显示错误页时，它被访问或更好，如何排除它访问?
您可以将此规则插入RewriteEngine On行下面:
# if request is for a .php file but not index.php then return forbidden
RewriteCond %{REQUEST_URI} !^/index'.php [NC]
RewriteRule '.php$ / [L,NC,R]
您可以通过以下设置检查:
ErrorDocument 404 http://www.example.com/error/404.html
注意:您需要为404.html提供路径。如果您正在使用任何框架，那么最有可能在错误模型目录中找到404.html文件。