我有一个简单的jquery模态框在我的网站。我在jquery的新，所以我不知道如何保持盒子打开，如果一个错误是对正在提交的表单构成。如果提交正确，重定向。
到目前为止，当出现错误时，它会重新加载页面，并且必须再次按弹出窗口以查看错误。
提前感谢。
if(isset($_POST['submit'])) {
$email = $_POST['email'];
if(empty($_POST['name']) || empty($_POST['email'])) {
$error = "Please enter the info in the fields that are marked <br /> with *";
}elseif(!filter_var($email, FILTER_VALIDATE_EMAIL)){
$error_email = "Please enter a valid email address";
}else{
$success = true;
$success = "Thank You";
mysql_query("INSERT INTO watch_list
(name, email) VALUES('".$_POST['name']."', '".$_POST['email']."')")
or die(mysql_error());
header( 'Location: /watch.php' );
}
}
<div class="play_wrapper">
<div class="play">
<a href="#" class="topopup"><img src="/styles/images/lx_play.png"/></a>
<div id="toPopup">
<div id="popup_content">
<div class="vid_form_text">
Please enter your name and email to watch the film. <span class="green">Thank you.</span>
</div>
<?php if(isset($success)) { ?>
<div class="success_watch">Thank You!</div>
<?php } ?>
<?php if(isset($error)) { ?>
<div class="error_watch">
<?php echo $error; ?>
</div>
<?php } ?>
<?php if(isset($error_email)) { ?>
<div class="error_watch">
<?php echo $error_email; ?>
</div>
<?php } ?>
<form method="post" action="#">
<div class="form_text_sign_up_required">
All fields marked with an asterisk * are required
</div>
<div class="form_text_sign_up">
Name*
</div>
<input type="text" name="name" value="<?php if(isset($_POST['name'])) {echo $_POST['name'];} ?>" /> <br /><br />
<div class="form_text_sign_up">
Email*
</div>
<input type="text" name="email" value="<?php if(isset($_POST['email'])) { echo $_POST['email'];} ?>" /><br /><br />
<input type='submit' name='submit' value='submit' class='post'/>
</form>
</div> <!--your content end-->
</div> <!--toPopup end-->
<div class="loader"></div>
<div id="backgroundPopup"></div>
</div>
</div>
<script>
jQuery(function($) {
$("a.topopup").click(function() {
loading(); // loading
setTimeout(function(){ // then show popup, deley in .5 second
loadPopup(); // function show popup
}, 500); // .5 second
return false;
});
/* event for close the popup */
$("div.close").hover(
function() {
$('span.ecs_tooltip').show();
},
function () {
$('span.ecs_tooltip').hide();
}
);
$("div.close").click(function() {
disablePopup(); // function close pop up
});
$(this).keyup(function(event) {
if (event.which == 27) { // 27 is 'Ecs' in the keyboard
disablePopup(); // function close pop up
}
});
$("div#backgroundPopup").click(function() {
disablePopup(); // function close pop up
});
$('a.livebox').click(function() {
alert('Hello World!');
return false;
});
/************** start: functions. **************/
function loading() {
$("div.loader").show();
}
function closeloading() {
$("div.loader").fadeOut('normal');
}
var popupStatus = 0; // set value
function loadPopup() {
if(popupStatus == 0) { // if value is 0, show popup
closeloading(); // fadeout loading
$("#toPopup").fadeIn(0500); // fadein popup div
$("#backgroundPopup").css("opacity", "0.7"); // css opacity, supports IE7, IE8
$("#backgroundPopup").fadeIn(0001);
popupStatus = 1; // and set value to 1
}
}
function disablePopup() {
if(popupStatus == 1) { // if value is 1, close popup
$("#toPopup").fadeOut("normal");
$("#backgroundPopup").fadeOut("normal");
popupStatus = 0; // and set value to 0
}
}
/************** end: functions. **************/
}); // jQuery End
</script>
您将需要使用AJAX来处理这个问题。如果您以JSON格式发送响应，则可以非常容易地解析出响应是否成功。
$('form').on('submit', function(e) {
var form = $('form')[0];
var data = new FormData(form);
// http://api.jquery.com/jQuery.ajax/
$.ajax({
url : 'Your URL',
data : data,
type: 'POST',
errror : function(xhr, status, err) {console.log(xhr, status, err);}, // This only gets thrown if form submits unsucessfully
success: function(response, status) {
// This assumes the response you're sending back from PHP is JSON
var data = JSON.parse(response);
if (data.error) {
// Handle form being unsuccessful
} else {
// Handle success
}
}
});
// This is to prevent the form from actually submitting.
e.preventDefault();
return false;
});