如何组合到多维数组的记录。我通过array_merge
合并了两个多维数组,数组合并后,我得到了一个数组。在这个数组中,我有元素receivable
, sale_date
, payables
和purchase_date
。
Array
(
[0] => Array
( [receivable] => 20 [sale_date] => 2014-06-24 )
[1] => Array
( [receivable] => 400 [sale_date] => 2014-06-28 )
[2] => Array
( [receivable] => 3410 [sale_date] => 2014-07-04 )
[3] => Array
( [receivable] => 923 [sale_date] => 2014-07-07 )
[4] => Array
( [receivable] => 1203 [sale_date] => 2014-08-15 )
[5] => Array
( [payables] => 9800 [purchase_date] => 2014-06-23 )
[6] => Array
([payables] => 0 [purchase_date] => 2014-06-24 )
[7] => Array
( [payables] => 16155 [purchase_date] => 2014-06-28 )
[8] => Array
( [payables] => 993 [purchase_date] => 2014-08-18 )
)
现在我想检查sale_date
和purchase_date
是否相同,然后我在数组中得到receivable
和payables
。如果它们不相同,那么我就得到原来的样子。我已经尝试了许多方法,但现在却碰壁了,不知道该怎么办。
这是我想要的结果:
Array
(
[0] => Array
( [purchase_date] => 2014-06-24 [sale_date] => 2014-06-24 [receivable] => 20 [payables] => 0 )
[1] => Array
( [sale_date] => 2014-06-28 [purchase_date] => 2014-06-28 [payables] => 16155 [receivable] => 400 )
[2] => Array
( [receivable] => 3410 [sale_date] => 2014-07-04 )
[3] => Array
( [receivable] => 923 [sale_date] => 2014-07-07 )
[4] => Array
( [receivable] => 1203 [sale_date] => 2014-08-15 )
[5] => Array
( [payables] => 9800 [purchase_date] => 2014-06-23 )
[6] => Array
( [payables] => 993 [purchase_date] => 2014-08-18 )
)
这是我的php代码:
$query_sale = "SELECT sum( `sale_received` ) AS receivable, `sale_date`
FROM `sale`
GROUP BY `sale_date`
ORDER BY `sale_date` ";
$result_sale = mysqli_query($con,$query_sale);
$query_purchase = "SELECT sum( `purchase_remaining` ) AS payables, `date`
FROM `purchase`
GROUP BY `date`
ORDER BY `date`";
$result_purchase = mysqli_query($con,$query_purchase);
$array_receivable = array();
$array_payables = array();
while($sale = mysqli_fetch_array($result_sale)){
$receivable = $sale['receivable'];
$sale_date = $sale['sale_date'];
$array_receivable[] = array('receivable' => $receivable , 'sale_date' => $sale_date);
}
while($purchase = mysqli_fetch_array($result_purchase)){
$payables = $purchase['payables'];
$purchase_date = $purchase['date'];
$array_payables[] = array('payables' => $payables , 'purchase_date' => $purchase_date);
}
$both_array = array_merge($array_receivable , $array_payables);
用这种方式编写返回数据的SQL查询可能更容易。
例如:SELECT (CASE WHEN B.date IS NULL THEN A.sale_date ELSE B.date END) As date, (CASE WHEN payables IS NOT NULL THEN payables ELSE 0 END) As payables,
CASE WHEN receivable IS NOT NULL THEN receivable ELSE 0 END) As receivable
FROM (SELECT sum( sale_received ) AS receivable, sale_date
FROM sale
GROUP BY sale_date) A
LEFT JOIN ( SELECT sum( purchase_remaining ) AS payables, date
FROM purchase
GROUP BY date ) B
ON A.sale_date = B.date
UNION
SELECT (CASE WHEN B.date IS NULL THEN A.sale_date ELSE B.date END) As date, (CASE WHEN payables IS NOT NULL THEN payables ELSE 0 END) As payables,
CASE WHEN receivable IS NOT NULL THEN receivable ELSE 0 END) As receivable
FROM (SELECT sum( sale_received ) AS receivable, sale_date
FROM sale
GROUP BY sale_date) A
RIGHT JOIN ( SELECT sum( purchase_remaining ) AS payables, date
FROM purchase
GROUP BY date ) B
ON A.sale_date = B.date
这将返回两个表中每个日期的应付账款和应收账款的值,如果特定日期只有一个值,则另一个值将为0。
也许在PHP中是这样的:
$query = "SELECT (CASE WHEN B.date IS NULL THEN A.sale_date ELSE B.date END) As date, (CASE WHEN payables IS NOT NULL THEN payables ELSE 0 END) As payables, ".
" CASE WHEN receivable IS NOT NULL THEN receivable ELSE 0 END) As receivable ".
"FROM (SELECT sum( sale_received ) AS receivable, sale_date ".
" FROM sale ".
" GROUP BY sale_date) A ".
"LEFT JOIN ( SELECT sum( purchase_remaining ) AS payables, date ".
" FROM purchase ".
" GROUP BY date ) B ".
"ON A.sale_date = B.date ".
"UNION ".
"SELECT (CASE WHEN B.date IS NULL THEN A.sale_date ELSE B.date END) As date, (CASE WHEN payables IS NOT NULL THEN payables ELSE 0 END) As payables, ".
" CASE WHEN receivable IS NOT NULL THEN receivable ELSE 0 END) As receivable ".
"FROM (SELECT sum( sale_received ) AS receivable, sale_date ".
" FROM sale ".
" GROUP BY sale_date) A ".
"RIGHT JOIN ( SELECT sum( purchase_remaining ) AS payables, date ".
" FROM purchase ".
" GROUP BY date ) B ".
"ON A.sale_date = B.date";
$result = mysqli_query($con,$query);
$both_array = [];
while($row = mysqli_fetch_array($result)){
$date = $row['date'];
$receivable = $row['receivable'];
$payable = $row['payables'];
$both_array[] = array('date' => $date , 'receivable' => $receivable, 'payable' => $payables);
}