可能重复：
使用php将字符串转换为2D数组
我有如下字符串：
01,03,02,15|05,04,06,10|07,09,08,11|12,14,13,16
如何将上面的字符串转换为定义的数组，如下面的数组：
$a[0] = array('column' => array("row1" => "01", "row2"=> "05", "row3" => "07", "row4" =>"12"));
$a[1] = array('column' => array("row1" => "03", "row2"=> "04", "row3" => "09", "row4" =>"14"));
$a[2] = array('column' => array("row1" => "02", "row2"=> "06", "row3" => "08", "row4" =>"13"));
$a[3] = array('column' => array("row1" => "15", "row2"=> "10", "row3" => "11", "row4" =>"16"));
我知道我应该使用爆炸函数，但不确定它应该如何实现，任何帮助都将不胜感激，谢谢！
使用这种格式，您基本上只需要：
$a = array_map("str_getcsv", explode("|", $string));
这将为您提供一个枚举数组。如果你想要你的特定命名密钥，那么你必须再次对这个结构进行后期处理：
foreach ($a as $i=>$row) {
$a[$i] = array("column" => array("row1"=>$row[0], "row2"=>$row[1], "row3"=>$row[2], "row4"=>$row[3]));
}
我想这就是您想要的：
<?php
$a = array();
$str = "01,03,02,15|05,04,06,10|07,09,08,11|12,14,13,16";
$arr = explode("|", $str);
for ($i = 0; $i < count($arr); $i++) {
$a[$i] = array('column' => array());
}
for ($i=0; $i<count($arr); $i++) {
$arr2 = explode(",", $arr[$i]);
for ($j = 0; $j < count($arr2); $j++) {
$key = "row" . intval($i + 1);
$a[$j]['column'][$key] = $arr2[$j];
}
}
echo "<pre>";
var_dump($a);
?>
$sequence = "01,03,02,15|05,04,06,10|07,09,08,11|12,14,13,16";
$columns = explode("|", $sequence);
$result = array();
foreach ($columns as $i => $column)
{
$rows = explode(",", $column);
$sub_array = array();
foreach ($rows as $id => $row)
{
$sub_array["row".($id+1)] = $row;
}
$result[$i] = array('column' => $sub_array);
}