我有一个关联数组,其中的键的编号与软件发布版本号类似,例如32.1
,我想做的是获取32.1
之后的每个版本(32.2、32.3、32.4等),并将它们分配给32
键下的另一个数组,因此我需要脚本是递归的,以便具有多个版本的较长版本号最终出现在正确的数组键中。
我的代码。。。
<?php
$array = array(
'1' => 'Level 1',
'1-1' => 'Level 1',
'1-2' => 'Level 1',
'1-2-1' => 'Sub-Level 1',
'2' => 'Level 2',
'3' => 'Level 3'
);
foreach ($array as $key => $value) {
static $assoc = array();
if (preg_match('/-/', $key)) {
$points = explode('-', $key);
$assoc_key = basename($key, '-' . end($points));
$assoc[$assoc_key]['sub'][$key] = array('1' => 'Sub-' . $array[end($points)]);
} else {
$assoc[$key] = array('1' => $array[$key]);
}
}
echo '<pre>' . print_r($assoc, true) . '</pre>';
?>
预期输出:
Array
(
[1] => Array
(
[1] => Level 1
[sub] => Array
(
[1-1] => Array
(
[1] => Sub-Level 1
)
[1-2] => Array
(
[1] => Sub-Level 2
[sub] => Array
(
[1-2-1] => Array
(
[1] => Sub-Sub-Level 1
)
)
)
)
)
[2] => Array
(
[1] => Level 2
)
[3] => Array
(
[1] => Level 3
)
)
实际输出
Array
(
[1] => Array
(
[1] => Level 1
[sub] => Array
(
[1-1] => Array
(
[1] => Sub-Level 1
)
[1-2] => Array
(
[1] => Sub-Level 2
)
)
)
[1-2] => Array
(
[sub] => Array
(
[1-2-1] => Array
(
[1] => Sub-Level 1
)
)
)
[2] => Array
(
[1] => Level 2
)
[3] => Array
(
[1] => Level 3
)
)
有人能帮忙吗?
我只知道我错过了一些简单的东西,但我已经试着让它发挥作用两天了。
我想出了一些可以使用数组引用解决问题的方法。
也许代码也可以进一步优化,但应该足以展示概念。
正如您所说,函数必须是递归的,但您使用了迭代方法。
<?php
$array = array(
'1' => 'Level 1',
'1-1' => 'Level 1',
'1-2' => 'Level 1.2',
'1-2-1' => 'Level 1.2.1',
'2' => 'Level 2',
'3' => 'Level 3'
);
$assoc = array();
foreach ($array as $key => $value) {
if (strpos($key, "-") !== false) {
$points = explode('-', $key);
$current = &$assoc[$points[0]];
$str = $points[0];
for ($i = 1; $i < count($points); $i++) {
$str .= "-" . $points[$i];
if (!isset($current["sub"]))
$current["sub"] = array();
$current = &$current["sub"][$str];
}
$current[1] = 'Sub-' . $value;
}
else {
$assoc[$key][1] = $array[$key];
}
}
echo '<pre>' . print_r($assoc, true) . '</pre>';
?>
**编辑:**您得到这种结果是因为当您构造$assoc_key
时,如果您得到$assoc_key='-12',则不应该构造$assoc[$assoc_key]['sub'][$key] = array('1' => 'Sub-' . $array[end($points)]);
,因为它将创建一个基id为'1-2'的新数组,您应该创建$assoc[$pre_asscokey]['sub'][$assoc_key][$key] = array('1' => 'Sub-' . $array[end($points)]);
所以试试这个:
<?php
$array = array(
'1' => 'Level 1',
'1-1' => 'Level 1',
'1-2' => 'Level 1',
'1-2-1' => 'Sub-Level 1',
'2' => 'Level 2',
'3' => 'Level 3'
);
static $assoc = array();
foreach ($array as $key => $value) {
if (preg_match('/-/', $key)) {
$points = explode('-', $key);
$assoc_key = basename($key, '-' . end($points));
$x=$points[0];
if($assoc_key == $pre_asscokey && sizeof($points)==3){
$assoc[$x]['sub'][$pre_asscokey]['sub'][$key] = array('1' => 'Sub-' . $array[end($points)]);
}else{
$assoc[$assoc_key]['sub'][$key] = array('1' => 'Sub-' . $array[end($points)]);
$pre_asscokey = $key;
}
} else {
$assoc[$key] = array('1' => $array[$key]);
$pre_asscokey=$key;
}
}
echo '<pre>' . print_r($assoc, true) . '</pre>';
?>
输出:
Array
(
[1] => Array
(
[1] => Level 1
[sub] => Array
(
[1-1] => Array
(
[1] => Sub-Level 1
)
[1-2] => Array
(
[1] => Sub-Level 2
[sub] => Array
(
[1-2-1] => Array
(
[1] => Sub-Level 1
)
)
)
)
)
[2] => Array
(
[1] => Level 2
)
[3] => Array
(
[1] => Level 3
)
)