我正在用Symfony2为眼镜商构建一个管理应用程序。当管理员向数据库中添加新客户时，我的控制器会检查客户名称是否重复。我想显示一个弹出对话框，询问用户是否要添加新客户。我该如何实现？我应该使用Ajax吗？以下是我在本例中使用的控制器的示例代码：
public function nouveauAction(Request $request)
{
$form = $this->createFormBuilder()
->add('nom','text')
->add('tel','text', array('label' => 'Nº de téléphone', 'data' => '06'))
->add('email','email', array('label' => 'E-mail', 'required' => false))
->add('date','date', array('label' => 'Date d''ajout', 'data' => new 'DateTime()))
->add('ajouter','submit')
->getForm()
;
$form->handleRequest($request);
if ($form->isValid()){
$client = new Client();
$client->setNomClient($form["nom"]->getData());
$client->setTelClient($form["tel"]->getData());
$client->setEmailClient($form["email"]->getData());
$client->setDateEditionClient($form["date"]->getData());
//just for now (Later we'll retrieve the username from the session)
$em = $this->getDoctrine()->getEntityManager();
$user = (new Utilisateur)->rechercherParPseudo($em, 'admin');
$client->setIdUtilisateur($user);
$em = $this->getDoctrine()->getEntityManager();
if($client->existe($em))
{
//I need a popup message here : The customer you are trying to add already exists""
}
else
{
$request = $this->container->get('request');
if($client->existeNomDouble($em)) //If the customer name is duplicate
{
//I need a popup message here with Yes/No buttons...
}
else
{
//Writing to the database:
$em = $this->getDoctrine()->getEntityManager();
$client->ajouterClient($em);
//A notification to fade in here : "Customer successfully added"
}
}
}
return $this->render('ClientBundle:Client:nouveau.html.twig', array(
'formAjouter' => $form->createView(),
));
}
试试这个：
控制器侧：
$this->get('session')->getFlashBag()->add(
'notice',
'Customer Added!'
);
视图侧面（细枝）：
{% for flashMessage in app.session.flashbag.get('notice') %}
<div class="alert alert-success">
{{ flashMessage }}
</div>
{% endfor %}
您是否在询问是否应该在单击按钮后使用ajax来显示弹出窗口？如果是这样，我建议使用ajax。以下是我以前在symfony中使用过的Bootstrap库，应该可以派上用场：http://vitalets.github.io/x-editable/