而PHP中的循环没有显示正确的数据。我正试图用SQL数据库填充我的菜单。它只给我DB事件的最后一个条目，尽管DB中有6个条目。
这是我的代码：
$top_sql = "SELECT * FROM menu_top_level /* WHERE top_level_visible = 'Yes' */ ORDER BY
top_level_order ASC"; // create a database query
$top_res = sqlsrv_query($conn, $top_sql) or die(sqlsrv_error($conn)); // check connection and execute query
if ($top_res = sqlsrv_query($conn, $top_sql)) { // if the query contains results...
Here >>>>>>>> while ($row = sqlsrv_fetch_array($top_res)) { // loop through each given row
$menu_block = "<div id='Accord' class='accord'><ul id='menu'>";
$menu_block .= "<li id='menubar'><a>".$row['2']."</a>";
/* echo "<pre>";
print_r($row);
echo "</pre>";*/
// Start: Build mid-level
$mid_sql = "SELECT * FROM menu_mid_level WHERE mid_level_fk_id = $row[top_level_pk_id] /* AND
mid_level_visible = 'Yes' */ ORDER BY mid_level_order ASC"; // create a database query
$mid_res = sqlsrv_query($conn, $mid_sql, array(), array("Scrollable"=>"buffered")) or die(sqlsrv_error($conn));
$mid_num_rows = sqlsrv_num_rows ($mid_res); // get number of row
//echo $mid_num_rows;
$mid_num_rows_constant = $mid_num_rows; // store number of row as a value
$mid_num_rows_counter = 0; // counter to match constant by adding 1 each loop (line 32)
if ($mid_num_rows == 0) { // unless if row count equals 0
$menu_block .= "</li>"; // close LI
} else if ($mid_num_rows > 0) { // otherwise if more than 0...
$menu_block .= "<ul class='sub'>"; // open UL for coming LI rows
}
if ($mid_res = sqlsrv_query($conn, $mid_sql)) { // if the query contains results...
while ($row = sqlsrv_fetch_array($mid_res)) { // loop through each given row
$menu_block .= "<li id='menubar'><a href='$row[mid_level_url]'>".$row[mid_level_name]."</a>";
$mid_num_rows_counter = $mid_num_rows_counter + 1; // mark row count as handled (line 60)
// Start: Build bot-level
$bot_sql = "SELECT * FROM menu_bot_level WHERE bot_level_fkt_id = $row[mid_level_fk_id]
AND bot_level_fkm_id = $row[mid_level_order] /* AND bot_level_visible = 'Yes' */
ORDER BY bot_level_order ASC";
//echo $bot_sql; // create a database query
$bot_res = sqlsrv_query($conn, $bot_sql, array(), array("Scrollable"=>"buffered")) or die(sqlsrv_error($conn));
$bot_num_rows = sqlsrv_num_rows ($bot_res);
//echo $bot_num_rows; // check number of rows
if ($bot_num_rows == 0) { // if no inner rows...
$menu_block .= "</li>"; // close above LI
} else if ($bot_num_rows > 0) { // otherwise if more than 0, it does contain...
$menu_block .= "<ul class='sub'>"; // so open UL to contain coming LI
}
if ($bot_res = sqlsrv_query($conn, $bot_sql)) { // if the query contains results...
while ($row = sqlsrv_fetch_array($bot_res)) { // loop through each given row
$menu_block .= "<li id='menubar'><a href='$row[bot_level_url]'>".$row[bot_level_name]."</a>
</li>"; // and output row result
$bot_num_rows = $bot_num_rows - 1; // keep counting back 1 each loop until...
if ($bot_num_rows == 0) { // check it is exactly 0...
$menu_block .= "</ul></li>"; // row has ended so close UL and LI
}
}
} // End: Build bot-level
}
} // End: Build mid-level
// if reached last row & provided there was more than 1 row, then close UL and LI
if ($mid_num_rows_counter == $mid_num_rows_constant && $mid_num_rows_counter > 1) {
$menu_block .= "</ul></li></ul></div>";
}
}
} // End: Build top-level
`
我认为您的错误在这一行：
$menu_block = "<div id='Accord' class='accord'><ul id='menu'>";
对于循环中的每一项，变量$menu_block都将重置为固定值
将该行更改为：
$menu_block .= "<div id='Accord' class='accord'><ul id='menu'>";
（注意.=）
您可能需要在循环上方的某个位置添加$menu_block='';
我发现了问题。
我的if语句论点不正确。循环到达第二个循环后停止。因为我检查循环是否应该退出的关闭if语句被设置为$variable>1而不是>=，所以它达到了1，它看到变量等于值1并退出
我替换了这个：
if ($mid_num_rows_counter == $mid_num_rows_constant && $mid_num_rows_counter > 1) {
$menu_block .= "</ul></li></ul></div>";
}
有了这个：
if ($mid_num_rows_counter == $mid_num_rows_constant && $mid_num_rows_counter >= 1) {
$menu_block .= "</ul></li></ul>";
}