在php中将图像从一个文件夹复制到子文件夹


copy images from one folder to sub folder in php

我面临一个问题。我有一些图像存储在D://图像中。我必须将这些图像复制到D://图像/已修改。我试过了,但没有得到任何输出。这是我的代码:

define("BASE_IMAGE_PATH","D:''");
define("IMAGE_FOLDER_NAME","2014finalfour''");
define("IMAGE_FOLDER_NAME_MODIFIED","modified");
define("IMAGE_File_Path",BASE_IMAGE_PATH.IMAGE_FOLDER_NAME);
define("IMAGE_File_Path_Modified", BASE_IMAGE_PATH.IMAGE_FOLDER_NAME.IMAGE_FOLDER_NAME_MODIFIED);
$srcdir=constant("IMAGE_File_Path");
$destdir=constant("IMAGE_File_Path_Modified");
echo $destdir;
if (!file_exists(IMAGE_File_Path_Modified))
{
    mkdir(IMAGE_File_Path_Modified, 0777, true);
}
$srcdir=opendir($srcdir);
while($readFile = readdir($srcdir))
{
    if($readFile != '.' && $readFile != '..')
    {
        if (!file_exists($readFile)) 
        {
            if(copy($srcdir . $readFile, $destdir . $readFile))
            {
                echo "Copy file";
            }
            else
            {
                echo "Canot Copy file";
            }
        }
    }
}
closedir($srcdir);

请帮我找一下。上面说不能复制文件。copy() expects parameter 1 to be a valid path, resource given in C:'wamp'www'marcs'testmysql.php on line 3

您可以使用copy()函数:copy('foo/test.php', 'bar/test.php');

示例:

<?php
$file = 'images/folder/one.jpg';
$newfile = 'Images/folder/one_thumb.jpg';
if (!copy($file, $newfile)) {
echo "failed to copy";
}

将文件源复制到dest。如果目标文件已经存在,它将被覆盖。