...
$php_array = mysqli_fetch_all($result,MYSQLI_ASSOC);
?>
<script type='text/javascript'>
<?php
$js_array = json_encode($php_array);
echo "var location = ". $js_array . ";'n";
?>
</script>
我如何修改上面给我这个输出的代码(我认为是一个对象数组？
var javascript_array = [
{"city":"Hermosa Beach","lat":"33.860069","lng":"-118.398784"},
{"city":"San Jose","lat":"34.694628","lng":"-118.398784"},
.... ]
给我这个... (数组数组？
var javascript_array = [
["Hermosa Beach",33.860069,-118.398784],
["San Jose",34.694628",-118.398784],
.... ]
没有一堆的...
调用mysqli_fetch_all()时使用MYSQLI_NUM而不是MYSQL_ASSOC。然后，这些行将是索引数组，而不是关联数组。
虽然我不知道你为什么希望数组是这样的。数组应该用于统一数据，对象应该用于异构数据。
谢谢，这有效并且非常精简...
<?php
$query = "SELECT * FROM file";
$result = $con->query($query);
// Fetch all rows and return the result-set as an associative array:
// using numeric keys for the array, instead of creating an associative array.
$php_array = mysqli_fetch_all($result,MYSQLI_NUM);
?>
<script type='text/javascript'>
<?php
// create a JSON representation of a value that javascript will understand
$js_array = json_encode($php_array);
// dump json object into javascript variable 'locations'
echo "var locations =" . $js_array . ";'n";
?>
</script>