我正在使用代码点火器中的from，程序控制正在移动到提交函数，我可以通过添加die函数来测试该函数。尽管set_rules（）成功地检查了条目，但控件没有传递给if（$this->form_validation->run（））这个函数。它退出并运行我一直用来测试程序流的die函数dead-2。
下面是我的控制器代码
function addPost(){
$this->load->library('form_validation')
if($this->admin_lib->checkMembers()){
if($this->input->post('submit')){
//validate the form
$this->form_validation->set_rules('country','Country','required');
$this->form_validation->set_rules('city','City','required');
$this->form_validation->set_rules('area','Area','required');
$this->form_validation->set_rules('street','Street','required');
$this->form_validation->set_rules('house_no','House number','required|numeric');
if($this->form_validation->run()){
//add to database
die("dead-1");
if($this->members_model->addPost())
{
echo "Successfully made one entry will be validated";
}
else{
echo "Error uploading the datas into database Please contact us about the problem";
}
}
die("Dead -2");
}
$data['content']=$this->load->view('members/addPost','',true);
$this->load->view('members/home',$data);
}
else{
echo "you dont have preveledge to access this page ,<br/> LOgin link rakhnu paryo ";
}
}
您的代码将始终调用die（"Dead-2"），因为它不是Else块的一部分。它位于If语句的正下方，这意味着，无论表单验证发生什么，它都会消亡。
考虑将代码更改为以下
if($this->form_validation->run())
{
//add to database
die("dead-1");
if($this->members_model->addPost())
{
echo "Successfully made one entry will be validated";
}
else
{
echo "Error uploading the datas into database Please contact us about the problem";
}
}
else
{
die("Dead -2");
}