我正在尝试显示与其类别相关的所有游戏,我在这里尝试的Sql只显示与游戏5相关的游戏,如何自动显示所有游戏?
<?php
$varCategoria_GameData = "0";
if (isset($_GET["cat"])) {
$varCategoria_GameData = $_GET["cat"];
}
$sql_categoria = "SELECT * FROM jogos WHERE intCategoria =
( SELECT intCategoria FROM jogos WHERE idGames = 5)";
$query_categoria = mysql_query($sql_categoria, $gameconnection) or die(mysql_error());
$categoria = mysql_fetch_assoc($query_categoria);
?>
<?php do { ?>
<?php echo '<h1>'.$categoria['idGames'].'</h1>'; ?>
<?php } while ($categoria = mysql_fetch_assoc($query_categoria)); ?>
您要从中删除"WHERE idGames=5"
$sql_categoria = "SELECT * FROM jogos";
查询以"WHERE idGames=5"结束,这实际上意味着它所说的内容。
然后,您可以通过以下方式从$categoria中提取字段:
$categoria['name_of_field'];
意大利语:
Devi togliere"WHERE idGames=5"e farla risultare così:
$sql_categoria = "SELECT * FROM jogos";
Quello chiede alla queryè
"从游戏中选择intCategoria,其中idGames=5";SELEZIONA intCategoria DA jogos DOVE idGamesè5
Poi da$categoria puoi estarre i campi in questo modo:
$categoria['nome_del_campo'];
<?php
$sql_categoria = "SELECT * FROM jogos";
$result_categoria = mysql_query($sql_categoria, $gameconnection) or die(mysql_error());
while($row = mysql_fetch_assoc($result_categoria))
{
//Use $row with the index of the field you want to display, or directly with the column name between quote.
echo "Result :".$row[0]."<br />";
}
?>
此外,请使用MySQLi函数:http://php.net/manual/fr/book.mysqli.php
避免SQL注入更安全