如果我想在一个页面上使用此代码两次或两次以上（稍作修改），我会收到以下错误消息：
"调用非对象上的成员函数fetch_assoc（）"
导致问题的代码行是：
while(($array_results[] = $results->fetch_assoc()) || array_pop($array_results));
代码已满如下：
<?PHP
if($_SESSION['member_unique_id']=="supermember"){
$results = $mysqli->query("SELECT client_organisation_name, client_id FROM clients ORDER BY client_organisation_name ASC");
}
else{
$results = $mysqli->query("SELECT client_organisation_name, client_id FROM clients WHERE member_unique_id='".$_SESSION['member_unique_id']."' ORDER BY client_organisation_name ASC");
}
while(($array_results[] = $results->fetch_assoc()) || array_pop($array_results));
echo '<div class="dashDropdown">'."'n";
foreach($array_results as $client) {
echo '<a href="create-a-property-2.php?client='.$client['client_id'].'" class="dashPropertyClientHover">'.$client['client_organisation_name'].'</a>'."'n";
}
echo '</div>'."'n";
$results->close();
$mysqli->close();
?>
如何修改它以防止错误消息出现，并防止此代码（稍微修改）在我的源代码中出现多次？我们一如既往地感谢您的帮助。
<?PHP
if($_SESSION['member_unique_id']=="supermember")
{
$results = $mysqli->query("SELECT client_organisation_name, client_id FROM clients ORDER BY client_organisation_name ASC");
}
else
{
$results = $mysqli->query("SELECT client_organisation_name, client_id FROM clients
WHERE member_unique_id='".$_SESSION['member_unique_id']."'
ORDER BY client_organisation_name ASC");
}
while($array_results = $results->fetch_assoc())
{
$client_id=$array_results['client_id'];
$client_org_name=$array_results['client_organisation_name'];
?>
<div class='dashDropdown'>
<a href="create-a-property-2.php?client=<?php echo $client_id;?>" class="dashPropertyClientHover">
<?php echo $client_org_name;?>
</a>
<?php echo "<br>";?>
</div>
<?php echo "<br>";?>
<?}
$results->close();
$mysqli->close();
?>