如何在foreach迭代中获取最后一个数组索引


How to get last array index inside foreach iteration?

我在StackOverflow上发现了一些类似的问题,但我的问题不同。我会尽量解释得更清楚。首先是阵列结构:$appointment

Array ( 
  [id_users_provider] => 85  
  [start_datetime] => 2015-11-15 17:15:00  
  [end_datetime] => 2015-11-15 17:15:00  
  [notes] =>  
  [is_unavailable] =>  
  [id_users_customer] => 87  
  [id_services] => 15 
)
Array (  
  [id_users_provider] => 85  
  [start_datetime] => 2015-11-15 17:15:00  
  [end_datetime] => 2015-11-15 17:15:00  
  [notes] =>  
  [is_unavailable] =>  
  [id_users_customer] => 87  
  [id_services] => 13  
)

如何查看$appointment变量中包含的两个数组。现在我想要得到最后一个数组的末尾,在本例中是id_services:13的数组。实际上,我通过appointment['id_services']执行了一次迭代。像这样:

foreach($appointment['id_services'] as $services)
{
   print_r(end($appointment));
}

但这个给我回了:

15
13

这是错误的,因为在这种情况下我只想得到13。我该怎么做?主要问题是在foreach循环内部检查实际的$services是否是foreach循环内最后一个数组的最后一个键。

伙计,为什么不只是end($appointment)['id_services']?在这种情况下,您为什么需要foreach

$last_appointment = end($appointment);
$id_services = $last_appointment['id_services'];
$id_services === 13; // true

foreach循环错误。。。。

两种简单的方法…

// using count (not recommended)
echo $appointment[count($appointment)-1]['id_services'];

//using end
echo end($appointment)['id_services'];

根据你的评论,你可能正在尝试这样做(我不明白为什么)

$last_appointment = end($appointment);
echo end($last_appointment);

修复您的代码

//not recommended!!
foreach(end($appointment) as $services)
{
   print_r(end($services));
}