代码点火器数据库where_in错误


codeigniter database where_in error

我感到困惑。我正在尝试以下查询:

$this->db->select('id')->from("orders")->where("status", "Active")->where_in($this->session->id, $this->db->query("SELECT `associated_staffs` FROM `orders` WHERE `status`='Active'")->result());
$total_rows = $this->db->count_all_results();

它生成以下 sql 查询:

SELECT COUNT(*) AS `numrows` FROM `orders` WHERE `status` = 'Active' AND 3 IN(, )

但它应该生成:

SELECT COUNT(*) AS `numrows` FROM `orders` WHERE `status` = 'Active' AND 3 IN(3,14,2 )

无论如何,我都不知道该怎么做。请帮忙

你可以

使用类似的东西

    $this->db->where(array('active' => 1));
    $this->db->from('cars'); //table name here
    $this->db->where_in('id', array(1, 2, 3, 3)); //pass yoru where_in values here
    $cars = $this->db->count_all_results();
    echo $cars;
    echo $this->db->last_query();

输出::

选择 COUNT(*( 作为numrowscars,其中 active = 1 和 id IN(1, 2, 3, 3(

试试这个简单的方法

$query = $this->db->query("SELECT id FROM orders WHERE status = 'Active' AND 3 IN(3,14,2)");
$result = $query->result_array();
return $result;

试试这个

  $this->db->select('COUNT(*) AS numrows');
  $this->db->from('orders');
  $this->db->where_in(3,array(3,14,2));
  $this->db->where('status','Active');
  $query=$this->db->get();
  $result=$query->row();
  echo $result->numrows;