获得超过10个结果谷歌搜索API - Getting more than 10 results Google Search API

Getting more than 10 results Google Search API

本文关键字：谷歌搜索 API 结果 10个 | 更新日期: 2023-09-27

我正在尝试使用搜索API从google获得10多个结果。我知道谷歌搜索API只给出10个结果，你必须调用它10次才能得到100个结果，但我似乎无法让它工作。我尝试创建一个do-while循环和for循环，但它似乎只是一遍又一遍地给我相同的结果。

<?php

if(isset($_GET['input']) && $_GET['input'] != "")
{
    echo "<br />Your Search Results Google:<br /><br />";

    $i=0;

    $url =  "http://ajax.googleapis.com/ajax/services/search/web?v=1.0&    key=AIzaSyBacVRiPNo7uMqhtjXG4Zeq1DtSQA_UOD4&cx=014517126046550339258:qoem7fagpyk
&num=10&start=".$i."&"."q=".str_replace(' ', '%20', $_GET['input'])
// sendRequest
// note how referer is set manually
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_REFERER, 'http://www.google.com');
$body = curl_exec($ch);
    curl_close($ch);


// now, process the JSON string


$json = json_decode($body,true); 

do
{
foreach ($json['responseData']['results'] as $data) {
echo '
    <p>
        ', $data ['title']," ---> <u>Google SE </u>" ,'<br />
        ', '<a href ='.$data['url'].'>'.$data['url']."</a>" , '<br />
        ', $data['content'],'
    </p>';
}
$i++;       
}
while($i<3);

}
?>

感谢任何意见。

好的。只需尝试以下代码：

<?php
if(isset($_GET['input']) && $_GET['input'] != "")
{
    echo "<br />Your Search Results Google:<br /><br />";
    for ($i = 0; $i < 10; $i++)
    {
        $url =  "http://ajax.googleapis.com/ajax/services/search/web?v=1.0&key=AIzaSyBacVRiPNo7uMqhtjXG4Zeq1DtSQA_UOD4&cx=014517126046550339258:qoem7fagpyk
            &num=10&start=".$i."&"."q=".str_replace(' ', '%20', $_GET['input']);
        $ch = curl_init();
        curl_setopt($ch, CURLOPT_URL, $url);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
        curl_setopt($ch, CURLOPT_REFERER, 'http://www.google.com');
        $body = curl_exec($ch);
        curl_close($ch);
        $json = json_decode($body,true);
        foreach ($json['responseData']['results'] as $data) {
            echo '
                <p>
                ', $data ['title']," ---> <u>Google SE </u>" ,'<br />
                ', '<a href ='.$data['url'].'>'.$data['url']."</a>" , '<br />
                ', $data['content'],'
                </p>';
        }
    }
}
?>