我正试图将值从AngularJS发送到PHP,如下所示
loginService.js
'use strict';
app.factory('loginService',function($http)
{
return{
login:function(user){
var promise = $http.post('data/user.php',user); //send data to user.php
promise.then(function(msg){
if(msg.data=='succes') console.log('succes login');
else console.log('error login');
})
}
}
});
我的PHP文件如下
user.php
<?php
$user=json_decode(file_get_contents('php://input'));
if($user->mail=='foysal@gmail.com' && $user->pass=='1234')
{
print 'succes';
}
else
{
print 'error';
}
?>
我的输出低于
error login
loginCtrl.js
'use strict';
app.controller('loginCtrl',function($scope,loginService)
{
$scope.login=function()
{
loginService.login();
}
})
有人能说出我的错误在哪里吗??
感谢
我收到这样的消息"<br />↵<b>Notice</b>: Trying to get property of non-object in <b>D:'php'htdocs'login_angularjs'app'data'user.php</b> on line <b>14</b><br />↵"
"
我如何在这里调试??比如,php文件正在获取值吗??php文件正在发送值吗??
更新
我想我没能收集到价值观来自HTML表单。我在这里给出HTML表单代码。你能帮我吗找出问题??
login.tpl.html
Welcome : {{user.mail}}
<div class="bs-example">
<form role="form" name="form1">
<div class="form-group">
<p>Welcome : {{user.mail}}</p>
<label for="exampleInputEmail">Mail</label>
<input type="text" placeholder="Enter name"
class="form-control" required ng-model="user.mail">
</div>
<div class="form-group">
<label for="exampleInputPassword">Password</label>
<input type="password" placeholder="Password"
id="exampleInputPassword" class="form-control" required
ng-model="user.pass">
</div>
<button class="btn btn-default" type="submit"
ng-disabled="form1.$invalid" ng-click="login(user)">Submit</button>
<p></p>
</form>
</div>
在PHP中需要这样的东西:
助手:
function getReturnObject ($message, $code) {
$response = new StdClass();
$response->message = $message;
$response->code = $code;
return $response;
}
主要代码:
print json_encode(getReturnObject('auth is successull', 200);
或者:
header('HTTP/1.0 403 Forbidden');
print json_encode(getReturnObject('auth is bad', 403);
然后在JavaScript中你需要这个:
var module = angular.module('myApp', []);
module.controller('myCtrl', ['$http', function ($http) {
var user = null; // some user
$http.post('data/user.php', user)
.success(function (data) {
// handle response there
})
.error(function (data) {
console.log('error');
});
}]);