如何在Zend框架中获得作为json对象的view.php文件？现在我在控制器中使用这个：
// in controller
public function helloAction()
{
$this->view->meta->title = 'Hello';
$this->view->meta->keywords = 'hello, wold, freebies';
$this->view->meta->description = 'Blah blah blah';
$this->render();
}
// in view *hello.php*
<div class="hello">Hello world</div>
我想在一个变量中捕获hello.php内容，比如这个
$html = $this->render();
$this->view->content = $html;
那么，使用这个？render=json我期待这样的结果
[view] => stdClass Object
(
[meta] => stdClass Object
(
[title] => Hello
[description] => hello, wold, freebies
[keywords] => Blah blah blah
)
[content] => stdClass Object
(
[view] => <div class="hello">Hello world</div>
)
)
这怎么可能？
您可以使用zend框架上下文切换操作助手
文档中的示例
class NewsController extends Zend_Controller_Action
{
public function init()
{
$contextSwitch = $this->_helper->getHelper('contextSwitch');
$contextSwitch->addActionContext('list', 'xml')
->initContext();
}
// ...
}