HttpURLConnection正在从.php文件返回垃圾

我一直在尝试从.php文件中获取JSON数据。它正在返回垃圾值。但如果我把url放在浏览器中，它会完美地向我显示json数据。这是的代码片段

    String authString = username + ":" + password;
    byte[] authEncBytes = Base64.encode(authString.getBytes(),0);
    String authStringEnc = new String(authEncBytes);
    URL url = new URL(urlString);
    HttpURLConnection httpConn = (HttpURLConnection) url.openConnection();
    httpConn.setAllowUserInteraction(false);
    httpConn.setInstanceFollowRedirects(true);
    httpConn.setRequestProperty("Content-type", "application/json");
    httpConn.setRequestProperty("Authorization", "Basic " + authStringEnc);
    httpConn.setRequestMethod("GET");
    httpConn.connect();
    InputStream stream = httpConn.getInputStream();

并将其从输入流转换为字符串

public static String convertinputStreamToString(InputStream ists)
        throws IOException {
    if (ists != null) {
        StringBuilder sb = new StringBuilder();
        String line;
        try {
            BufferedReader r1 = new BufferedReader(new InputStreamReader(
                    ists, "UTF-8"));
            while ((line = r1.readLine()) != null) {
                sb.append(line).append("'n");
            }
        } finally {
            ists.close();
        }
        return sb.toString();
    } else {
        return "";
    }
}

显而易见的是，如果我带了"某人"，它会返回奇怪的垃圾值。看起来像js代码，就像下面的

函数toNumbers（d）{var e=[]；d.replace（/（..）/g，函数（d）｛e.push（parseInt（d，16））｝）；return e｝函数toHex（）｛for（var d=[]，d=1==arguments.length&&arguments[0]。constructor==Array？arguments[0]：arguments，e="，f=0；fd[f]？"0"："）+d[f].toString（16）；return e.toLowerCase（）｝var a=toNumbers（"f655ba9d09a112d4968c63579db590b4"），b=toNumerics（"98344c2eee86c3994890592585b49f80"），c=toNumberes（"72355c058989 7edf080a57d7f54b23a51e"）；document.cookie="__test="+toHex（slowAES.decrypt（c，2，a，b））+"；过期时间=12月31日星期四-37 23:55:55 GMT；路径=/"；document.cookie="referrer="+转义（document.referrer）；位置。href="http://emgcall.byethost9.com/getData.php?ckattempt=1"；此网站需要Javascript才能工作，请在浏览器中启用Javascript或使用支持Javascript的浏览器

我已经尝试在php文件中将内容设置为Application/Json。同样的结果。

问题和解决方案可能是什么。

这是php代码

    <?php
    header('Content-type: application/json');
    function x(){
    $con=mysqli_connect("com","","","");
    if (mysqli_connect_errno($con)){
       echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }
    $sql = "SELECT * FROM emgCall";
    $result = mysqli_query($con,$sql);
    if (mysqli_num_rows($result) > 0) {
        $response["numbers"] = array();
        while($row = mysqli_fetch_assoc($result)){
            $number = array();
            $number['id']=$row['id'];
            $number['number']=$row['number'];
            $number['image']=base64_encode($row['image']);
            array_push($response["numbers"], $number);
        }
        $son=json_encode($response);
        mysqli_close($con);
        return $son;
    } else {
        $outputs["success"] = 0;
        $outputs["message"] = "No products found";
    }
  }
  echo $data = x();
   ?>