我正在处理一个高级搜索查询,用户可以根据多个条件选择复选框。我是一个初学者,所以我希望我能发现我是否走在正确的轨道上。我知道这个问题很混乱。
编辑:我意识到这需要两个问题,所以我修改为严格的查询问题
表数据
Table ss_users
user_id first_name last_name admin_level user_approved
1 nick jones 0 1
2 johnny rocket 0 1
Table ss_user_profile_status
user_id photo_uploaded
1 1
2 1
Table ss_user_photos
photo_id user_id filename selected
1 1 photo_1.jpg 1
2 2 photo_2.jpg 0
3 2 photo_2.jpg 1
Table ss_general
user_id city state zip neighborhood
1 baltimore maryland 00125 hamsterdam
2 lakeland maine 11542 treemont
Table ss_languages
user_id french german italian spanish
1 0 1 0 1
2 0 0 1 1
Table ss_experience
user_id waldorf kumon homeschooling
1 0 1 0
2 0 0 1
我目前的结果是所有用户,不应该是这样的:
SELECT
ss_users.*, ss_user_profile_status.*, ss_user_photos.*, ss_general.*,
ss_languages.*, ss_experience.*, ss_users.user_id AS userID,
ss_user_profile_status.user_id, ss_languages.user_id AS langID
FROM
ss_users
JOIN
ss_user_profile_status ON ss_users.user_id = ss_user_profile_status.user_id
LEFT JOIN
ss_user_photos ON ss_users.user_id = ss_user_photos.user_id
AND
ss_user_photos.selected = 1
LEFT JOIN
ss_languages ON ss_users.user_id = ss_languages.user_id
LEFT JOIN
ss_general ON ss_users.user_id = ss_general.user_id
LEFT JOIN
ss_experience ON ss_users.user_id = ss_experience.user_id
WHERE
ss_users.user_id = ss_user_profile_status.user_id
AND
ss_general.neighborhood_select LIKE '%hamsterdam%'
OR
ss_languages.spanish = 1
OR
ss_experience.kumon = 1
AND
ss_users.sitter_approved = 1
AND
ss_users.admin_level = 0
GROUP BY
ss_users.user_id DESC
对于我需要表示大部分用户配置文件的输出,这就是我选择大量表数据以及额外联接的原因。
对于您的大型SQL选择
SELECT
ss_users.*, ss_user_profile_status.*, ss_user_photos.*, ss_general.*,
ss_languages.*, ss_experience.*, ss_users.user_id AS userID,
ss_user_profile_status.user_id, ss_languages.user_id AS langID
FROM ss_users
JOIN ss_user_profile_status ON ss_users.user_id = ss_user_profile_status.user_id
LEFT JOIN ss_user_photos ON ss_users.user_id = ss_user_photos.user_id AND ss_user_photos.selected = 1
LEFT JOIN ss_languages ON ss_users.user_id = ss_languages.user_id
LEFT JOIN ss_general ON ss_users.user_id = ss_general.user_id
LEFT JOIN ss_experience ON ss_users.user_id = ss_experience.user_id
WHERE
( ss_general.neighborhood_select LIKE '%hamsterdam%' OR ss_languages.spanish = 1 OR ss_experience.kumon = 1 ) AND ss_users.sitter_approved = 1 AND ss_users.admin_level = 0
我只编辑了一些地方,比如在OR周围添加括号,并删除了第一个条件,因为它看起来是多余的,还删除了组,因为它会将一些数据排除在之外