MySQL高级搜索查询多个条件


MySQL Query for Advanced Search multiple criteria

我正在处理一个高级搜索查询,用户可以根据多个条件选择复选框。我是一个初学者,所以我希望我能发现我是否走在正确的轨道上。我知道这个问题很混乱。

编辑:我意识到这需要两个问题,所以我修改为严格的查询问题

表数据

Table ss_users
user_id  first_name   last_name   admin_level   user_approved  
1        nick         jones       0             1      
2        johnny       rocket      0             1      
Table ss_user_profile_status
user_id  photo_uploaded   
1        1
2        1
Table ss_user_photos
photo_id  user_id  filename      selected
1         1        photo_1.jpg   1
2         2        photo_2.jpg   0
3         2        photo_2.jpg   1
Table ss_general
user_id  city        state      zip     neighborhood
1        baltimore   maryland   00125   hamsterdam
2        lakeland    maine      11542   treemont
Table ss_languages
user_id  french  german  italian  spanish
1        0       1       0        1
2        0       0       1        1
Table ss_experience
user_id  waldorf  kumon  homeschooling 
1        0       1       0
2        0       0       1

我目前的结果是所有用户,不应该是这样的:

SELECT 
    ss_users.*, ss_user_profile_status.*, ss_user_photos.*, ss_general.*, 
    ss_languages.*, ss_experience.*, ss_users.user_id AS userID, 
    ss_user_profile_status.user_id, ss_languages.user_id AS langID
FROM 
    ss_users
JOIN 
    ss_user_profile_status ON ss_users.user_id = ss_user_profile_status.user_id
LEFT JOIN 
    ss_user_photos ON ss_users.user_id = ss_user_photos.user_id
AND 
    ss_user_photos.selected = 1
LEFT JOIN 
    ss_languages ON ss_users.user_id = ss_languages.user_id
LEFT JOIN 
    ss_general ON ss_users.user_id = ss_general.user_id
LEFT JOIN 
    ss_experience ON ss_users.user_id = ss_experience.user_id
WHERE 
    ss_users.user_id = ss_user_profile_status.user_id 
AND 
    ss_general.neighborhood_select LIKE '%hamsterdam%'
OR 
    ss_languages.spanish = 1
OR 
    ss_experience.kumon = 1
AND 
    ss_users.sitter_approved = 1
AND 
    ss_users.admin_level = 0
GROUP BY 
    ss_users.user_id DESC

对于我需要表示大部分用户配置文件的输出,这就是我选择大量表数据以及额外联接的原因。

对于您的大型SQL选择

SELECT 
    ss_users.*, ss_user_profile_status.*, ss_user_photos.*, ss_general.*, 
    ss_languages.*, ss_experience.*, ss_users.user_id AS userID, 
    ss_user_profile_status.user_id, ss_languages.user_id AS langID
FROM ss_users
    JOIN ss_user_profile_status ON ss_users.user_id = ss_user_profile_status.user_id
    LEFT JOIN ss_user_photos ON ss_users.user_id = ss_user_photos.user_id AND ss_user_photos.selected = 1
    LEFT JOIN ss_languages ON ss_users.user_id = ss_languages.user_id
    LEFT JOIN ss_general ON ss_users.user_id = ss_general.user_id
    LEFT JOIN ss_experience ON ss_users.user_id = ss_experience.user_id
WHERE 
    ( ss_general.neighborhood_select LIKE '%hamsterdam%' OR ss_languages.spanish = 1 OR ss_experience.kumon = 1 ) AND ss_users.sitter_approved = 1 AND ss_users.admin_level = 0

我只编辑了一些地方,比如在OR周围添加括号,并删除了第一个条件,因为它看起来是多余的,还删除了组,因为它会将一些数据排除在之外