我正在尝试将php文件的代码显示为纯html。这一切都进展顺利，除了我希望它也"打开"<?php require 'Main_content_bar.php'; ?>陈述的事实。
到目前为止，我已经show_source($page);正常工作。
它当前打印：
<?php require 'Main_content_bar.php'; ?>
<!-- Jumbotron -->
<div class="jumbotron">
<h1>Property</h1>
<p class="lead">Cras justo odio, dapibus ac facilisis in, egestas eget quam. Fusce dapibus, tellus ac cursus
commodo, tortor mauris condimentum nibh, ut fermentum massa justo sit amet.</p>
</div>
<div class="row">
<div class="col-md-12">
<h2>Current properties</h2>
</div>
</div>
<div class="footer">
<p><a href="Source_code.php" target="_blank"> <img src="Images/codebutton<?php echo $page_lower;?>.jpg" alt="<?php echo $page;?> Source"> </img>
</a></p>
<p>© Robin B'stards Retail 2014</p>
</div>
</body>
</html>
但是，如您所见，require语句的内容并未显示。我一辈子都想不出该怎么做。
所以它最终看起来像这样：
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<script src="jquery-2.1.1.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.2.0/js/bootstrap.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.2.0/css/bootstrap.min.css">
<!-- <link rel="stylesheet" href="//cdnjs.cloudflare.com/ajax/libs/jquery.bootstrapvalidator/0.5.2/css/bootstrapValidator.min.css"/>-->
<!-- <script type="text/javascript" src="//cdnjs.cloudflare.com/ajax/libs/jquery.bootstrapvalidator/0.5.2/js/bootstrapValidator.min.js"></script>-->
<link href="justified-nav.css" rel="stylesheet">
<script>
$(function(){
var url = window.location.href;
var page = url.substr(url.lastIndexOf('/')+1);
$('.nav a[href*="'+page+'"]').parent().addClass('active');
});
</script>
</head>
<body>
<div class="container" style="width: 1263px">
<div class="masthead">
<h3 class="text-muted">Ruthless Real Estate</h3>
<ul class="nav nav-justified">
<li class="menu"><a href="Property.php">Property</a></li>
<li class="menu"><a href="Client.php">Client</a></li>
<li class="menu"><a href="Type.php">Type</a></li>
<li class="menu"><a href="Feature.php">Feature</a></li>
<li class="menu"><a href="Multiple_properties.php">Multiple Properties</a></li>
<li class="menu"><a href="Property_features.php">Property Features</a></li>
<li class="menu"><a href="Images.php">Images</a></li>
</ul>
</div>
<!-- Jumbotron -->
<div class="jumbotron">
<h1>Property</h1>
<p class="lead">Cras justo odio, dapibus ac facilisis in, egestas eget quam. Fusce dapibus, tellus ac cursus
commodo, tortor mauris condimentum nibh, ut fermentum massa justo sit amet.</p>
</div>
<div class="row">
<div class="col-md-12">
<h2>Current properties</h2>
</div>
</div>
<div class="footer">
<p><a href="Source_code.php" target="_blank"> <img src="Images/codebutton<?php echo $page_lower;?>.jpg" alt="<?php echo $page;?> Source"> </img>
</a></p>
<p>© Robin B'stards Retail 2014</p>
</div>
</body>
</html>
注意缺少 require 语句
你不能
用show_source做到这一点，它只是"显示文件的一些代码源"。
您需要创建自己的函数，该函数在参数中采用文件名，然后您必须像这样分析源代码：
- 将所有要求/包含/require_once/include_once(我忘记了什么？(替换为他们自己的内容
- 使函数递归(因为Main_content_bar.php里面可以包含其他内容(
- 在函数末尾使用
highlight_string。
编辑搜索和替换，一种方法(有几种(是使用preg_match_all。这部分代码如下所示：
$new_content = file_get_contents('your-file.php');
$base_path = __DIR__.'/';
// pattern to find require, require_once, include, include_once functions
// and catch their arguments
$pattern = "#<'?php (?:require|include(?:_once)?)'s*'(.*)'; '?>#u";
if (preg_match_all($pattern, $new_content, $matches))
{
foreach($matches[0] as $pattern_index => $full_pattern)
{
$file = $matches[1][$pattern_index];
$subcontent = file_get_contents($base_path.$matches[$pattern_index]);
$new_content = str_replace($new_content, $full_pattern, $subcontent);
}
}
highlight_string($new_content);