jQuery -在PHP while循环中检查一个输入框与另一个输入框


jQuery - Checking an input box against another input box in a PHP while loop

我在编写订单提交页面时遇到了一个相当大的问题,该页面的目的是提交订单的争议-提供两个字段填写,但只有当一个字段小于另一个字段时。

基本上一个是下拉框,另一个是争议框,查询如下:

如果争端testextbox = "和下拉框= "Please Select…"

一切正常-提交按钮启用

如果testextbox = "和下拉框= "Please select…"

错误(反之亦然,所以如果争议填充但下拉=请选择…)-提交按钮禁用

如果

一切正常-提交按钮启用

错误-提交按钮被禁用

<table>
                <thead>
                    <tr><th>Item ID</th><th>Description</th><th>Dispute Quantity</th><th>Shipped Quantity</th><th>Ordered Quantity</th><th>Reason</th></tr>
                </thead>
                <tbody>
                    <?php
                        $data = mysql_query("SELECT * FROM `artran09` WHERE `invno` = '$invoiceno'") or die(mysql_error());
                        echo "<center>";
                        $i = -1;        
                        echo "<form action='"submitdispute.php?invno=".$invoiceno."&ordate=".$placed."'" method='"POST'" onsubmit='"return confirm('Are you sure you are ready to dispute your order?');'">";
                            while ($info = mysql_fetch_array($data)) {              
                                $i += 1;                                    
                                echo "<tr>"; 
                                echo "<td>".$info['item']."</td>"; 
                                echo "<td>".$info['descrip']."</td>";       
                                echo "<td><input type='"text'" input name=".$i." onKeyPress='"return numbersonly(this, event)'"  maxLength='"3'"></td>"; 
                                echo "<td><input type='"text'" value=".$info['qtyshp']." onKeyPress='"return numbersonly(this, event)'" maxLength='"3'" disabled='"disabled'"></td>"; 
                                echo "<td><input type='"text'" value=".$info['qtyord']." onKeyPress='"return numbersonly(this, event)'" maxLength='"3'" disabled='"disabled'"></td>"; 
                                echo "<td><select name = '"reason$i'">";
                                echo "<option>Please Select...</option>";
                                echo "<option>Short/Not received</option>";
                                echo "<option>Damaged Goods</option>";
                                echo "<option>Product Not Ordered</option>";                    
                                echo "</select></td>";
                                echo "</tr>"; 
                            }
                    ?>
                </tbody>
            </table>
        </div>
    </div>
    <p><input type = "submit" value = "Dispute" name ="Submit">
    </form>

谢谢,希望有人能帮忙!

为Wolf/任何可以帮助的人编辑-这里的代码是怎么回事:

——我编辑的代码——

function validateSubmit(){

   // this will loop through each row in table
   // Make sure to include jquery.js
   $('tr').each( function() {
      // Find first input
      var input1 = $(this).find('input').eq(0);
      var qty1 = input1.val();
      // Find Second input
      var input2 = $(this).find('input').eq(1);
      var qty2 = input2.val();
      // Find third input
      var input3 = $(this).find('input').eq(2);
      var qty3 = input3.val();
      // Find select box
      var selectBx = $(this).find('select');
      var selectVal = selectBx.val();
      // Add your validation code here for the inputs and select
      // Return true if all validations are correct
      // Else return false
        if(qty1 = "" && selectVal = "Please Select...") {
            return true;
            alert("You have an error somewhere, please check over your quantites.");
            break;
        }
        if (qty1 > qty2) {
            return false;
            alert("You have an error somewhere, please check over your quantites.");
            break;
        }
   });

}
        return true;
        alert("You have an error somewhere, please check over your quantites.");
        break;

如果调用return,将立即停止当前函数的执行并返回值。这意味着return语句之后什么都不执行。alert()将不会运行,因为函数以return true结束。

相关文章: