我尝试创建一个对所有json请求都唯一的类，并尝试将json请求从它发送到服务器。它只接受请求url和json StringEntity。请求发送，但问题是当我试图从服务器访问数据时找不到发布数据。
JSONClinet.java
package info.itranfuzz.service;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import android.util.Log;
public class JSONClient {
private final HttpClient httpClient;
private HttpPost httpPost;
private HttpResponse httpResponse;
public JSONClient() {
httpClient = new DefaultHttpClient();
}
public String doPost(String url, StringEntity se) {
InputStream inputStream = null;
String result = "";
httpPost = new HttpPost(url);
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
httpPost.setEntity(se);
try {
httpResponse = httpClient.execute(httpPost);
inputStream = httpResponse.getEntity().getContent();
if (inputStream != null)
result = convertInputStreamToString(inputStream);
else
result = "Did not work!";
} catch (Exception e) {
Log.d("InputStream", e.getLocalizedMessage());
}
return result;
}
private static String convertInputStreamToString(InputStream inputStream)
throws IOException {
BufferedReader bufferedReader = new BufferedReader(
new InputStreamReader(inputStream));
String line = "";
String result = "";
while ((line = bufferedReader.readLine()) != null)
result += line;
inputStream.close();
return result;
}
}
服务器帐户代码在这里。有电子邮件、lat和lng要发送到服务器。
<?php
//set content type to json
header('Content-type: application/json');
$email = $this->input->post("email");
$lat = $this->input->post('lat');
$lng = $this->input->post('lng');
$status = array("STATUS"=>"false");
if($this->donor->updateLocationByEmail($email,$lat,$lng)){
$status = array("STATUS"=>"true");
}
array_push($status, array("email"=>$email,"lat"=>$lat,"lng"=>$lng));
echo json_encode($status);
?>
我的呼叫方式是这个
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
JSONClient jClient = new JSONClient();
Location loc = new Location(LocationService.this);
LatLng p = loc.getLocation();
if (p != null) {
String json = "";
try {
JSONObject jsonObject = new JSONObject();
// jsonObject.accumulate("email", WebLoad.STORE.getEmail());
jsonObject.put("email", "b@gmail.com");
jsonObject.put("lat", p.getLat());
jsonObject.put("lng", p.getLng());
json = jsonObject.toString();
System.out.println(jClient.doPost(WebLoad.ROOTURL
+ "/donor_controller/updatelocation", new StringEntity(
json)));
} catch (JSONException e) {
System.out.println("Json exception occur");
} catch (UnsupportedEncodingException e) {
System.out.println("Unsupported ecodding exception occur");
}
}
return super.onStartCommand(intent, flags, startId);
}
//import packages
public class DBConnection {
static InputStream is = null;
static JSONObject jsonObject = null;
static String json = "";
// This is a constructor of this class
public DBConnection() {
}
/*
* function get jsonObject from URL by making HTTP POST or GET method.
*/
public JSONObject createHttpRequest(String url, String method,
List<NameValuePair> params) {
// Making HTTP request
try {
// check for request method
if (method == "POST") {
// request method is POST and making default client.
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(params));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} else if (method == "GET") {
// request method is GET
DefaultHttpClient httpClient = new DefaultHttpClient();
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}
} catch (UnsupportedEncodingException ex) {
ex.printStackTrace();
} catch (ClientProtocolException ex) {
ex.printStackTrace();
} catch (IOException ex) {
ex.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "'n");
}
is.close();
json = sb.toString();
Log.w("Error" ,"My Error" + json);
} catch (Exception ex) {
Log.e("Buffer Error", "Error converting result " + ex.toString());
}
// try to parse the string to a JOSN object
try {
Log.w("sub",json.substring(json.indexOf("{"), json.lastIndexOf("}") + 1));
jsonObject = new JSONObject(json.substring(json.indexOf("{"), json.lastIndexOf("}") + 1));
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return new object
return jsonObject;
}
}
请你用这种方式提出要求。
$email = $this->input->$_POST('email')
用这种方式做任何尝试。将post更改为$_post["变量名"]。正如我所说的，您编写的是服务器端PHP。在PHP获取和发布方法中，我们访问$_get和$_post。