我正在尝试使用PHP计算存储在数据库记录中的单词"Saturday"的数量。它没有正确计数。我在那栏里只有三条记录：星期六、星期六、周日当我打印$row["Repeating"]时，它会将所有记录显示为Saturday Saturday，其中Saturday的计数器必须为2，而Sunday的计数器为1。我的计数器工作不正常星期六我拿到的柜台价是3英镑，星期天是3英镑。我看不出这个错误。有什么想法我会很感激的。
谢谢
$numberofWcounters = mysqli_num_rows($result);
$dementiacounter1 = 1;
// count Saturday.
$counterSaturday=0;
// count sunday
$counterSunday=0;
while( $counter <= $numberofWcounters)
{
if ($row['Day'] ='Saturday')
{
$counterSaturday++;
}
if ($row['Repeating'] ='Sunday')
{
$counterSunday++;
}
$counter++;
}
echo $row['Repeating'] ;
echo "<br />The number of Saturday for repeating question are : " . $$counterSaturday ;
您似乎没有在结果集上迭代，这意味着您在同一行（结果集中的第一行）上循环3次
您必须使用mysqli_fetch或等效工具来确保实际访问查询生成的每个不同结果。
$result->bind_result( $day, $repeating );
while( $result->fetch() ) {
// in every iteration of this loop, $day is $row['Day'] and $repeating is $row['Repeating'] of a new row
if ($day =='Saturday')
{
$counterSaturday++;
}
if ($repeating == 'Sunday')
{
$counterSunday++;
}
}