F.e。我有$game对象，有3张截图$game->screen1，$game->screen2，$game->screen3
我需要获得像$game['screen'.$num]这样的数据，但在Object中。
您可以为此使用数组：
$game->screen = array($screen1, $screen2, $screen3);
$game->screen[$num];
您可以这样做：
$game->screen2 = 'this is screen2';
$num = 2;
echo $game->{'screen' . $num}; // "this is screen2"
$game->screen3 = 'this is screen3';
$num = 3;
echo $game->{'screen' . $num}; // "this is screen3"