数组值来分配php中的变量


Array Values to assign the variables in php

数组值以分配php:中的变量

Array
    (
        [0] => stdClass Object
            (
                [Id] => 116249
                [Amount] => 51.62
                [Currency] => INR
                [ExchangeRate] => 1
                [InvoiceDate] => 2015-12-16T00:00:00Z
                }
       [1] => stdClass Object
            (
                [Id] => 116250
                [Amount] => 55.20
                [Currency] => KWD
                [ExchangeRate] => 1
                [InvoiceDate] => 2015-12-16T00:00:00Z
                }
       [2] => stdClass Object
            (
                [Id] => 116251
                [Amount] => 59.42
                [Currency] => USD
                [ExchangeRate] => 1
                [InvoiceDate] => 2015-12-16T00:00:00Z
                }  
    }
foreach ($invoice as $key => $value) 
{
        $Id=$value->Id;
        $Amount=$value->Amount;
        $Currency=$value->Currency;
        $ExchangeRate=$value->ExchangeRate;
        $invoiceDate = str_replace('Z', '', str_replace('T', ' ',$value->InvoiceDate)); 

 }            

  $jsonData ='[{"Id": "'.$Id.'",
                "Amount": "'.$Amount.'",
                "Currency": "'.$Currency.'",
                "ExchangeRate": "'.$ExchangeRate.'",
                "invoiceDate": "'.$invoiceDate.'"}];

我试过这个代码最后一个数组值只打印数组[2]值,我需要像一样的输出

[{"Id": "116249",
                    "Amount": "51.62",
                    "Currency": "INR",
                    "ExchangeRate": "1",
                    "invoiceDate": "2015-12-16T00:00:00Z"},
                    {"Id": "116250",
                    "Amount": "55.20",
                    "Currency": "KWD",
                    "ExchangeRate": "1",
                    "invoiceDate": "2015-12-16T00:00:00Z"},
                    {"Id": "116251",
                    "Amount": "59.42",
                    "Currency": "USD",
                    "ExchangeRate": "1",
                    "invoiceDate": "2015-12-16T00:00:00Z"}]

我同意Liam的观点,json_encode()可能是解决您问题的最佳方案。然而,如果你正在寻找一个DIY解决方案,它很简单:

$jsonData = '[';
foreach ($invoice as $key => $value) 
{
        $Id=$value->Id;
        $Amount=$value->Amount;
        $Currency=$value->Currency;
        $ExchangeRate=$value->ExchangeRate;
        $invoiceDate = str_replace('Z', '', str_replace('T', ' ',$value->InvoiceDate)); 
        // Append the next invoice's JSON data to all of the JSON data
        $jsonData .='{"Id": "'.$Id.'",
                "Amount": "'.$Amount.'",
                "Currency": "'.$Currency.'",
                "ExchangeRate": "'.$ExchangeRate.'",
                "invoiceDate": "'.$invoiceDate.'"},';
 }
 // Clean up and close off the JSON data:
 $jsonData = rtrim($jsonData, ','); // remove the trailing comma
 $jsonData .= ']'; // Add the closing bracket.

您在代码中遇到的问题是,在foreach循环运行后,您只分配了一次JSON数据。相反,您需要将每个发票的JSON数据附加到其他发票的JSON数据中。

尽管如此,json_encode()可能是更好的解决方案,因为它是一行,更容易阅读,而且可以说更容易理解。

您想要从数组创建json字符串。你所需要做的就是运行以下

jsonData = json_encode($invoice);

如果您想使用循环来创建数组,只生成特定的值,那么您可以执行以下操作:

$tmp = array();
foreach ($invoice as $key => $value) 
{
   $tmp["id"] = $value->Id;
   $tmp["amount"] = $value->Amount;
   $tmp["Currency"] = $value->Currency;
   $tmp["ExchangeRate"] = $value->ExchangeRate;
   $tmp["invoiceDate"] = str_replace('Z', '', str_replace('T','',$value->InvoiceDate));
 }  
jsonData = json_encode($tmp);

*编辑*

如果您对invoiceData变量使用mysql日期。那么您最好使用PHP日期函数。