最近我鼓励在PHP代码中出现奇怪的错误。这就像在将PDOStatement对象与foreach(){}
一起使用时省略了内部try{}catch(){}
块。这是我触发这种行为的测试代码:
<?php
/*
// THIS WORKS AS EXPECTED, JUST UNCOMMENT
try{
for($i = 0; $i < 3; $i++){
try{
echo "'nTHROWING EXCEPTION'n'n";
throw new Exception("AAAAAAAAAAAAAAAAAAAAAAAAA");
echo "EXCETION THROWN (SHOULD NOT SHOW)'n";
}catch(Exception $err){
echo "========= INNER CATCH ========='n";
echo $err->getMessage() . "'n";
}
}
}catch(Exception $e){
echo "=========== OUTER CATCH ==========='n";
die($e->getMessage() . "'n");
}
die("'nEVERYTHING OK'n");
*/
$dsn = "mysql:dbname=test_pdo;host=localhost";
try {
$dbh = new PDO($dsn, 'root', "", array(PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8"));
$dbh->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$dbh->exec("
CREATE TABLE IF NOT EXISTS `test` (
`id` int(10) unsigned NOT NULL,
`name` varchar(255) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `name` (`name`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
");
$dbh->exec("TRUNCATE test");
$dbh->exec("
INSERT INTO test (id, name) VALUES
(1, 'JOHN DOE 1'), (2, 'JOHN DOE 2'),
(3, 'JOHN DOE 3'), (4, 'JOHN DOE 4')
");
echo "'nRECORDS CREATED'n";
$sth = $dbh->prepare("SELECT id FROM test WHERE id = ?");
foreach(array(2, 3, 4) as $id){
$sth->execute(array($id));
$i = 0;
foreach($sth as $row){
$num = $row['id'] - 1;
// this sql should throw 2300 error duplicate key
$sql = "UPDATE test SET name = 'JOHN DOE $num' WHERE id = {$row['id']}";
try{
echo "'nSENDING QUERY: $sql'n'n";
$dbh->exec($sql);
}catch(Exception $err){
$code = $err->getCode();
$msg = $err->getMessage();
//duplicate key error?
if($err->getCode() != "23000"){
echo "THROWING EXCEPTION FROM INNER CATCH.'n ERROR CODE: $code'n";
throw $err;
}
echo <<<TXT
============ GOOD CATCH ============
ERROR CODE: $code
ERROR MSG: $msg
SQL: $sql
TXT;
}
}
}
}catch(Exception $e){
$code = $e->getCode();
$msg = $e->getMessage();
echo <<<TXT
============ WRONG CATCH ===========
ERROR CODE: $code
ERROR MSG: $msg
TXT;
}
这在我的本地主机(PHP 5.3.6-13ubuntu3.6和Suhosin Patch(cli))和服务器(PHP 5.2.17)上输出类似的内容:
RECORDS CREATED
SENDING QUERY: UPDATE test SET name = 'JOHN DOE 1' WHERE id = 2
============ GOOD CATCH ============
ERROR CODE: 23000
ERROR MSG: SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry 'JOHN DOE 1' for key 'name'
SQL: UPDATE test SET name = 'JOHN DOE 1' WHERE id = 2
============ WRONG CATCH ===========
ERROR CODE: 23000
ERROR MSG: SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry 'JOHN DOE 1' for key 'name'
不知道为什么,但当我将foreach($sth as $row){
更改为foreach($sth->fetchAll() as $row){
时,一切都如预期:
RECORDS CREATED
SENDING QUERY: UPDATE test SET name = 'JOHN DOE 1' WHERE id = 2
============ GOOD CATCH ============
ERROR CODE: 23000
ERROR MSG: SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry 'JOHN DOE 1' for key 'name'
SQL: UPDATE test SET name = 'JOHN DOE 1' WHERE id = 2
SENDING QUERY: UPDATE test SET name = 'JOHN DOE 2' WHERE id = 3
============ GOOD CATCH ============
ERROR CODE: 23000
ERROR MSG: SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry 'JOHN DOE 2' for key 'name'
SQL: UPDATE test SET name = 'JOHN DOE 2' WHERE id = 3
SENDING QUERY: UPDATE test SET name = 'JOHN DOE 3' WHERE id = 4
============ GOOD CATCH ============
ERROR CODE: 23000
ERROR MSG: SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry 'JOHN DOE 3' for key 'name'
SQL: UPDATE test SET name = 'JOHN DOE 3' WHERE id = 4
我是发现了错误还是做错了什么?有人能证实这种行为吗?Thx
//编辑
将PHP版本升级到5.3.10似乎可以解决这个问题。寻求帮助。。。
不,从PDO发回的结果不是可以直接迭代的。这不是PDO的例外,当你尝试这样做时,它是一个PHP——它不是一个数组或一个有迭代器的对象。
获取时,它会创建一个在foreach循环中有效的数组。