我正在阅读作者Kent Beck的《示例测试驱动开发》一书。
我正在尝试用php编写一个类似的函数,但不理解其中的步骤。
原始功能:
测试功能:
public void testEquality() {
assertTrue(new Dollar(5).equals(new Dollar(5)));
assertFalse(new Dollar(5).equals(new Dollar(6)));
}
类功能:
public boolean equals(Object object) {
Dollar dollar = (Dollar) object;
return amount == dollar.amount;
}
我的代码:
测试功能:
public function setup() {
$this->dollarFive = new Dollar(5);
}
public function testEquality() {
$this->assertTrue($this->dollarFive->equals(new Dollar(5)));
}
类函数:
class Dollar
{
public function __construct($amount) {
$this->amount = (int) $amount;
}
public function equals(Dollar $object) {
$this->Object = $object;
return $this->amount == $this->Object;
}
}
在执行测试用例时,我得到了以下错误。
Dollar类的对象无法转换为int
需要一些帮助。我该怎么解决这个问题?
return $this->amount == $this->Object;
$this->amount
是int,$this->Object
不是int。你试图相互比较,这样你就会得到
Dollar类的对象无法转换为int
你可能是指
return $this->amount == $this->Object->amount;
然而,在你的课堂中也有一些奇怪的东西
class Dollar {
public $amount = 0; // <-- forgotten
public function __construct($amount) {
$this->amount = (int) $amount;
}
public function equals(Dollar $object) {
$this->Object = $object; // <--- ?!?
return $this->amount == $this->Object;
}
}
你可能只想要
public function equals(Dollar $object) {
return $this->amount == $object->amount;
}