通过弹出链接传递 PHP 变量

调用弹出窗口时，我需要通过链接传递变量。像我通常一样添加变量时，名称与弹出窗口不匹配。

这是我所拥有的：

<a data-toggle="modal" href="#allMessages?id=<?php echo $job['job_id']; ?>" class="btn btn-warning btn-sm btn-icon">
  <i class="fa fa-unlock-alt"></i>View All Messages
</a>

    <div class="modal fade" id="allMessages" tabindex="-1" role="dialog" aria-labelledby="allMessages" aria-hidden="true">
                <div class="modal-dialog">
                    <div class="modal-content">
                        <div class="modal-header success">
                            <button type="button" class="close" data-dismiss="modal" aria-hidden="true"><i class="fa fa-times"></i></button>

                            <h4 class="modal-title">Reply</h4>
                        </div>
                            <?php
                                $getMessages = mysqli_query($mysqli, 
                                "SELECT *
                                FROM messages 
                                WHERE messages.job_id = $GET['id']
                                "
                                );
                                $messages = array(); 
                                    while($message = mysqli_fetch_assoc($getMessages)) {
                                          $messages[] = $message;
                                }

问题是当我在按钮链接的末尾添加变量时 #allMessages？id= 它不再调用弹出窗口。

Javascript：

        $("[data-toggle='popover']").popover();
});
function load_page() {
    var selected_page = document.getElementById("selected_page").value;
    if (selected_page != "") {
        window.location.href = selected_page
        //Please note that the value recived,
        //in this case selected_page,
        //should be a valid url!
        //Therefore the value of the
        //<option> tag should be itself 
        //a url !
        //ex.: <option value="page.php"> is valid
        //<option value="page_1"> is not valid
    }