大家好:)我是编程界的新手，所以我真的需要你们的帮助。我试图从一些数据库表中获取数据，不幸的是，在我的$. getjson()函数中出现了问题。如果我运行php文件，它的工作，所以从脚本.js函数。我的html也可以，所以我想它是$get。JSON的错。我不懂那么多javascript，所以我把所有的希望都寄托在你身上:*
html文件: <!doctype html>
<html>
<head>
<meta charset="utf-8" />
<title>jQuery Ajax - PHP</title>
<script type="text/javascript" src="jquery.js"></script>
</head>
<body>
<script src="script.js">
</script>
</body>
</html>
script.js文件:
$('document').ready( function() {
done();
}
);
function done() {
setTimeout(function() {
updates();
done();
}
, 200 );
}
function updates(){
$.getJSON( "read.php", function (data){
$.each(data.array, function () {
$("body").append("<li>Titlu: "+this['title']+"</li>
<li>Descriere: "+this['describtion']+"</li>");
}
);
$.each(data.array1, function () {
$("body").append("<li>Id: "+this['id']+"</li>
<li>Category_Id: "+this['category_id']+"</li>
<li>Titlu: "+this['title']+"</li>
<li>Descriere: "+this['describtion']+"</li>");
}
);
$.each(data.array2, function () {
$("body").append("<li>Id: "+this['id']+"</li>
<li>Titlu: "+this['title']+"</li>
<li>Latitudine: "+this['location_latitude']+"</li>
<li>Longitudine:"+this['location_longitude']+"</li>
<li>Numar de telefon: "+this['phone_number']+"</li>
<li>Descriere: "+this['describtion']+"</li>");
}
);
$.each(data.array3, function () {
$("body").append("<li>Id: "+this['id']+"</li>
<li>Interest_point_id:"+this['interest_point_id']+"</li>
<li>Pret: "+this['price']+"</li>
<li>Data: "+this['event1_time']+"</li>");
}
);
}
);
}
最后是read.php文件(这里它显示了我所期望的，所以我认为一切都很好):
<?php
include_once ('db.php');
$query= "SELECT * FROM category";
$query1= "SELECT * FROM sub_category";
$query2= "SELECT * FROM interest_point";
$query3= "SELECT * FROM event1";
global $connect;
$result = mysqli_query($connect,$query);
$result1 = mysqli_query($connect,$query1);
$result2 = mysqli_query($connect,$query2);
$result3 = mysqli_query($connect,$query3);
$array = array();
$array1 = array();
$array2 = array();
$array3 = array();
while($row=mysqli_fetch_array($result))
array_push($array , array( 'id' => $row[0],
'title' => $row[1],
'describtion' => $row[2]
));
while($row1=mysqli_fetch_array($result1))
array_push($array1 , array( 'id' => $row1[0],
'category_id' => $row1[1],
'title' => $row1[2],
'describtion' => $row1[3]
));
while($row2=mysqli_fetch_array($result2))
array_push($array2 , array('id' => $row2[0],
'title' => $row2[1],
'location_latitude' => $row2[2],
'location_longitude'=> $row2[3],
'phone_number' => $row2[4],
'describtion' => $row2[5]
));
while($row3=mysqli_fetch_array($result3))
array_push($array3 , array(
'id' => $row3[0],
'interest_point_id'=> $row3[1],
'price' => $row3[2],
'event1_time' => $row3[3]
));
echo json_encode(array("array"=>$array)).'<br>'.'<br>';
echo json_encode(array("array1"=>$array1)).'<br>'.'<br>';
echo json_encode(array("array2"=>$array2)).'<br>'.'<br>';
echo json_encode(array("array3"=>$array3)).'<br>'.'<br>';
?>
发送json时只能返回一次，并且只能有一个php数组包含所有数据。您不能在此之外打印任何内容，例如<br>标记
尝试改变
echo json_encode(array("array"=>$array)).'<br>'.'<br>';
echo json_encode(array("array1"=>$array1)).'<br>'.'<br>';
echo json_encode(array("array2"=>$array2)).'<br>'.'<br>';
echo json_encode(array("array3"=>$array3)).'<br>'.'<br>';
$output = array(
"array1"=>$array1,
"array2"=>$array2,
"array3"=>$array3
);
echo json_encode($output);
还要注意<li>是<body>的无效子节点。使用<div>或插入<ul>