我在一个bootstrap Modal内建立一个表单,它有3个INPUT
字段和Submit
按钮为每一行。每个Submit
都是另一个页面上的POST
。然后,我要做的是使用变量将数据返回到一个表中,该表将显示该特定搜索(如邮政编码,街道名称)的所有结果。在表中,我有一个SUBMIT
按钮,它将把输出返回到主页面上的主表单。
我正在努力的部分是从INPUT
(从我的模式,我在jobdetailssearch.php上使用)到POST
到搜索页面(search.php)的变量。返回后,我将在jobdetails页面(jobdetails.php)
下面是我的3个页面的代码。
jobdetailssearch.php
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true"></button>
<h4 class="modal-title">Search Projects</h4>
</div>
<div class="modal-body">
<form class="modal-form" id="searchform" name="searchform" action="includes/search.php" method="post">
<div class="form-group">
<label class="col-md-4 control-label">Project Number</label>
<div class="col-md-6">
<input type="text" class="form-control input-inline input-medium" name="searchprojno" id="searchprojno" placeholder="Enter Project Number">
</div>
<button type="submit" class="btn blue" id="submitsearchprojno" name="submitsearchprojno" >Search <i class="m-icon-swapright m-icon-white"></i></button>
</div>
<div class="form-group">
<label class="col-md-4 control-label">Address</label>
<div class="col-md-6">
<input type="text" class="form-control input-inline input-medium" name="searchaddress" id="searchaddress" placeholder="Enter Address">
</div>
<button type="submit" class="btn blue" id="submitsearchadd" name="submitsearchadd" >Search <i class="m-icon-swapright m-icon-white"></i></button>
</div>
<div class="form-group">
<label class="col-md-4 control-label">Postcode</label>
<div class="col-md-6">
<input type="text" class="form-control input-inline input-medium" name="searchpostcode" id="searchpostcode" placeholder="Enter Postcode">
</div>
<button type="submit" class="btn blue" id="submitsearchpc" name="submitsearchpc" >Search <i class="m-icon-swapright m-icon-white"></i></button>
</div>
<div class="form-group">
<div class="col-md-12">
<div class="table-responsive">
<table class="table table-striped table-bordered table-advance table-hover">
<thead>
<tr>
<th width="100px"><i class="fa fa-list-alt"></i> Address</th>
<th width="50px"></th>
</tr>
</thead>
<tbody>
<tr>
<td width="100px"></td>
<td width="50px"><a href="#" class="btn default btn-xs blue-stripe">Select Address</a></td>
</tr>
</tbody>
</table>
</div>
</div>
</div>
<div class="modal-footer right">
<button type="button" data-dismiss="modal" class="btn default">Cancel</button>
<!--<button type="submit" class="btn blue">Select</button>-->
</div>
</form>
</div>
search.php
<?php
require '../core/cnn.php';
if(isset($_POST['submitsearchprojno'])) {
$searchprojno = $_POST["searchprojno"];
}
if(isset($_POST['submitsearchadd'])) {
$searchaddress = $_POST["searchaddress"];
}
if(isset($_POST['submitsearchpc'])) {
$searchpostcode = $_POST["searchpostcode"];
}
$searchpostcode = mysql_real_escape_string($searchpostcode);
$searchaddress = mysql_real_escape_string($searchaddress);
$searchprojno = mysql_real_escape_string($searchprojno);
$searchrs = mysql_query("SELECT ProjectNo, CONCAT(COALESCE(HouseNoName, ''), ' ', COALESCE(StreetName, ''), ' ',
COALESCE(TownOrCity, ''), ' ', COALESCE(Postcode, '')) AS Display,
PropID, AreaID, AWGMember, Householder, HouseNoName, StreetName, TownOrCity,
Postcode, ContactTelephone, AlternatePhone, Email, PropertyTenure, PropertyNotes
FROM prop_property
WHERE IsActive = 1
AND (Postcode = '".$searchpostcode."'
OR StreetName = '".$searchaddress."'
OR ProjectNo = '".$searchprojno."')
") or die(mysql_error());
$checkrs = mysql_query("SELECT * FROM prop_property WHERE IsActive = 0");
if(!mysql_num_rows($checkrs) > 0) {
echo '<td> No record found!</td><td></td>';
}
else {
while ($results = mysql_fetch_array($searchrs)) {
echo '
<td>'.$results['Display'].'</td>
<td>
<form action="jobdetails.php" method="post">
<input type="hidden" name="searchhouse" value=" '.$results['HouseNoName'].'" >
<input type="hidden" name="searchstreet" value=" '.$results['StreetName'].'" >
<input type="hidden" name="searchtown" value=" '.$results['TownOrCity'].'" >
<input type="hidden" name="searchpostcode" value=" '.$results['Postcode'].'" >
<input type="hidden" name="searchpropid" value=" '.$results['PropID'].'" >
<input type="hidden" name="searchprojectno" value=" '.$results['ProjectNo'].'" >
<button type="submit" class="btn default btn-xs blue-stripe" name="viewsearch">View Address</button>
</form>
</td>';
}
}
?>
模式打开良好,并以我想要的方式显示表单。什么是最好的方式,我应该去这个输入搜索条件,并在一个表中显示结果,让我选择和拉上我的jobdetails.php上的主表单(我没有包括这个,因为它太大了,不确定它需要被看到)?
让我知道如果我理解你的问题,你有你的表单在引导的模态视图,你想发送表单中的数据到另一个页面,处理搜索,然后返回数据,你发现相同的模态,并把它放入<这就是你的问题?>
好吧,如果是的话。我认为更简单的方法是使用jquery,改变输入按钮的输入提交,我不太记得了在模态中发送提交时,模态是关闭的。这是真的吗?如果出现这个问题,请更改按钮的提交。然后,你必须为按钮创建一个函数。click()来捕获事件click,使用。serialize() (如果你想检查你是否真的在接收数据,你可以做一个die(var_dump($_POST));在PHP中使用firebug或类似的工具在控制台中进行检查),您将获得<然后你必须发送它与一个。post()到另一个文件,在php中你收到的数据,当你收到响应,你可以把它放入表与。html()。>
所以我想的代码应该是这样的,你可以改变它,使它成为你需要的,但这可以是基础:
JQUERY代码:$(document).ready(function(){
$("#yourButtonID").click(function(){
data = $("#yourFormID").serialize();
$.post("yourPHPfileToSearch.php",data,function(dataReturn)){
$("#yourTableID").html(dataReturn);
});
});
});
如果你需要更多的帮助,告诉我。的问候。祝你过得愉快。