正在检查会员状态和登录


Checking membership status and loggin in

有人能把我推向正确的方向,告诉我这段代码出了什么问题吗。我没有收到任何错误,但它也没有将我登录。这个想法是在sql数据库中有一个名为memb的行,并检查状态是1还是0。如果是1,它会把你带到安全页面,如果是0,它会给你订阅页面

<?php

require_once('config.php');  

if(isset($_POST['Login']) && isset($_POST['uname']) && isset($_POST['pass1'])) {
// Here check if all input are sent 
$uname = $sql-> real_escape_string($_POST['uname']);
$pass1 = $sql-> real_escape_string($_POST['pass1']);

 if ( !empty($uname) && !empty($pass1)) {
  // Check if you input are not empty
  $query= mysqli_query($sql,"SELECT * FROM login WHERE uname='".$uname."' AND pass='".$pass1."' && memb='?'");
  if(!$query){ die(mysqli_error($sql)); }
  $checkuser= mysqli_num_rows($query);

  if($checkuser != 1) {

   $error = "Username doesn't exist in our database!";
  }
  // Change $login with $query
  while ($row = mysqli_fetch_array($query)) {
   $checkpass= $row['pass'];
 while ($row = mysqli_fetch_array($query)) { 
   $checkmemb= $row['memb'];   
   // here i changed $pass1 to $checkpass
   if ($pass1 == $checkpass && $memb == 0){
    setcookie("user", $uname, time()+7200);
    $_SESSION['user'] = $uname;
    $_SESSION['start'] = time();
    $_SESSION['expire'] = $_SESSION['start'] + (60 * 60 * 60);
    header("Location: pay.php");
    exit();
   } elseif($pass1 == $checkpass && $memb == 1) {
     setcookie("user", $uname, time()+7200);
    $_SESSION['user'] = $uname;
    $_SESSION['start'] = time();
    $_SESSION['expire'] = $_SESSION['start'] + (60 * 60 * 60);
    header("Location: main.html");
    exit();
   }
  }
 }
 }
 }

尝试更改此项:

if(isset($_POST['Login']) && isset($_POST['uname']) && isset($_POST['pass1'])) {
// Here check if all input are sent 

至:

if(isset($_POST['uname']) && isset($_POST['pass1'])) {
// Here check if all input are sent 

没有测试,这只是一个快速的猜测。但它似乎什么都没做,因为您的输入检查失败了。