我想构建一个查询，它返回所有图像的产品，而不仅仅是一个图像。
这是我提取产品的模型
function get_latest($id){
$this->db->select('*');
$this->db->from('products');
$this->db->join('products_pictures', 'products_pictures.id_product = products.id_product', 'left');
$this->db->join('thumbs', 'thumbs.id_thumb = products_pictures.id_thumb', 'left');
$this->db->join('images', 'images.id_image = thumbs.id_image', 'left');
$this->db->order_by('date_c', 'DESC');
$this->db->limit($id);
$query = $this->db->get();
return $query->result();
}
这是输出
0 =>
object(stdClass)[35]
public 'id_product' => string '1000' (length=4)
public 'name' => string 'Graham Corners' (length=14)
public 'description' => string 'Et ea quaerat totam temporibus quis. Ut fugiat blanditiis vel corporis minus veniam. Consequatur corporis sint sed assumenda itaque ratione ipsum distinctio. Voluptate autem quo sunt rerum.' (length=189)
public 'date_c' => string '2015-12-28 03:12:59' (length=19)
public 'date_u' => null
public 'id_category' => string '7' (length=1)
public 'id_user' => string '173' (length=3)
public 'alias' => string 'graham-corners' (length=14)
public 'active' => string '1' (length=1)
public 'id_product_thumb' => string '4996' (length=4)
public 'id_thumb' => string '4996' (length=4)
public 'thumb_path' => string 'http://lorempixel.com/250/150/?22290' (length=36)
public 'id_image' => string '4996' (length=4)
public 'image_path' => string 'http://lorempixel.com/1024/768/?77489' (length=37)
1 =>
object(stdClass)[36]
public 'id_product' => string '1000' (length=4)
public 'name' => string 'Graham Corners' (length=14)
public 'description' => string 'Et ea quaerat totam temporibus quis. Ut fugiat blanditiis vel corporis minus veniam. Consequatur corporis sint sed assumenda itaque ratione ipsum distinctio. Voluptate autem quo sunt rerum.' (length=189)
public 'date_c' => string '2015-12-28 03:12:59' (length=19)
public 'date_u' => null
public 'id_category' => string '7' (length=1)
public 'id_user' => string '173' (length=3)
public 'alias' => string 'graham-corners' (length=14)
public 'active' => string '1' (length=1)
public 'id_product_thumb' => string '4997' (length=4)
public 'id_thumb' => string '4997' (length=4)
public 'thumb_path' => string 'http://lorempixel.com/250/150/?87585' (length=36)
public 'id_image' => string '4997' (length=4)
public 'image_path' => string 'http://lorempixel.com/1024/768/?76756' (length=37)
由于我不想获取所需产品的所有图像，我需要构建一个查询，该查询将输出存储在某个数组或其他东西中的对象产品下的所有产品图像
所需的输出对象应与此类似
0 =>
object(stdClass)[35]
public 'id_product' => string '1000' (length=4)
public 'name' => string 'Graham Corners' (length=14)
public 'description' => string 'Et ea quaerat totam temporibus quis. Ut fugiat blanditiis vel corporis minus veniam. Consequatur corporis sint sed assumenda itaque ratione ipsum distinctio. Voluptate autem quo sunt rerum.' (length=189)
public 'date_c' => string '2015-12-28 03:12:59' (length=19)
public 'date_u' => null
public 'id_category' => string '7' (length=1)
public 'id_user' => string '173' (length=3)
public 'alias' => string 'graham-corners' (length=14)
public 'active' => string '1' (length=1)
public 'images' => array (
[0] => stdClass Object
public 'id_thumb' => string '4998' (length=4)
public 'thumb_path'=> string 'http://lorempixel.com/250/150/?87585' (length=36)
public 'id_image' => string '4998' (length=4)
public 'image_path' => string 'http://lorempixel.com/1024/768/?76756' (length=37)
[1] => stdClass Object
public 'id_thumb' => string '4997' (length=4)
public 'thumb_path'=> string 'http://lorempixel.com/250/150/?87585' (length=36)
public 'id_image' => string '4997' (length=4)
public 'image_path' => string 'http://lorempixel.com/1024/768/?76756' (length=37)
........................
)
提前感谢
对我来说，应该只将id_thumb组合为id_thumbs，而不是将所有图像数据组合到images列中。例如：
function get_latest($id)
{
$this->db->select('products.*,product_pictures.*');
$this->db->select('GROUP_CONCAT(product_pictures.id_thumb) as id_thumbs',FALSE);
$this->db->from('products');
$this->db->join('products_pictures', 'products_pictures.id_product = products.id_product', 'left');
$this->db->order_by('date_c', 'DESC');
$this->db->group_by('id_product');
$this->db->limit($id);
$query = $this->db->get();
return $query->result();
}
在您的模型中，创建一个名为get_image_data_by_id_thumb的函数，如下所示：
function get_image_data_by_id_thumb($id_thumb='')
{
if($id_thumb=='')
{
return false;
}
$this->db->where('id_thumb', $id_thumb);
$this->db->join('images', 'images.id_image = thumbs.id_image', 'left');
$sql = $this->db->get('thumb');
$obj = $sql->row();
if($obj)
{
return $obj;
}
}
输出为：
0 =>
object(stdClass)[35]
public 'id_product' => string '1000' (length=4)
public 'name' => string 'Graham Corners' (length=14)
public 'description' => string 'Et ea quaerat totam temporibus quis. Ut fugiat blanditiis vel corporis minus veniam. Consequatur corporis sint sed assumenda itaque ratione ipsum distinctio. Voluptate autem quo sunt rerum.' (length=189)
public 'date_c' => string '2015-12-28 03:12:59' (length=19)
public 'date_u' => null
public 'id_category' => string '7' (length=1)
public 'id_user' => string '173' (length=3)
public 'alias' => string 'graham-corners' (length=14)
public 'active' => string '1' (length=1)
public 'id_thumbs' => '4998,4997,...'
然后，您可以通过id_thumb使用分解方法获取图像数据：
$arr_id_thumbs = explode(",",$id_thumbs);
foreach($arr_id_thumbs as $row)
{
$obj_image_data = $this->model_name->get_image_data_by_id_thumb($id_thumb);
$thumb_path = $obj_image_data->thumb_path;
$image_path = $obj_image_data->image_path;
.......................
}
希望能有所帮助。