我试图在div中显示存储在不同文件夹中的3个缩略图
在我的bd中确定(值为"1")哪个记录有图片。这就是我的数据库:
+------+----------------+---------+--------+--------+
| ID | BRAND | PHP | RUBY | JAVA |
+------+----------------+---------+--------+--------+
| 1 | ford | 1 | 0 | 0 |
+------+----------------+---------+--------+--------+
| 2 | seat | 1 | 1 | 1 |
+------+----------------+---------+--------+--------+
| 3 | fiat | 1 | 1 | 0 |
+------+----------------+---------+--------+--------+
| 4 | toyota | 1 | 0 | 0 |
+------+----------------+---------+--------+--------+
| 5 | vw | 1 | 0 | 1 |
+------+----------------+---------+--------+--------+
选择记录:
$result = mysqli_query($connecDB,"SELECT * FROM brands WHERE php = '1' OR ruby = '1' OR java = '1' ORDER BY id ASC");
while($row = mysqli_fetch_assoc($result)){
$new_array[] = $row;
}
但我的问题是:如何选择值"1"以及如何知道哪个是哪个
也许我可以使用:$row['php'] $row['java'] $row['ruby']
但是如何过滤值"0"?
看起来您想要将数组分解为php、java和ruby。下面没有经过测试,只是给你一个想法。
$resultsArray = array();
while($row = mysqli_fetch_assoc($result)){
if($row['php'] == 1) {
$resultsArray['php'][] = $row['id'];
}
if($row['java'] == 1) {
$resultsArray['java'][] = $row['id'];
}
if($row['ruby'] == 1) {
$resultsArray['ruby'][] = $row['id'];
}
}
然后循环遍历那个2d数组,从resultsArray中的键中获取名称。
foreach($resultsArray as $language => $array) {
foreach($array as $id) {
echo "url/".$language."/".$id;
echo "<br>";
}
}
foreach($resultsArray as $language => $array){
foreach(array_slice(glob('work/'.$language.'/'.$rowtest['id'].'/*.jpg'),0,1) as $image){
echo $image . "<br />";
}
}