我无法获得将params绑定到Mysql查询的代码,我做错了什么?
错误
致命错误:未捕获的异常"PDOException",消息为"SQLSTATE[HY093]":无效参数编号:绑定变量的数量与/Users/warren/Sites/Frame-Work/Modules/User Login/classes/db.php:34堆栈跟踪:#0/Users/warren/Sites/Frame Work/Modules/User Login/classes/db.phpLogin/classes/db.php(48):dbConnect->get_contents()#2{main}在第34行的/Users/warren/Sites/Frame-Work/Modules/User Login/classes/db.php中抛出
代码
<?php
include '../../../../config.php';
$dbUser = $config['username'];
$dbPass = $config['password'];
class dbConnect {
public function connect($dbUser,$dbPass) {
$this->dbUser = $dbUser;
$this->dbPass = $dbPass;
try {
$this->connect = new PDO('mysql:hostname=localhost;dbname=totalrisk', $this->dbUser, $this->dbPass);
$this->connect->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
return $this->connect;
} catch (Exception $e) {
echo 'ERROR: ' . $e->getMessage();
}
}
public function select_table($table) {
$this->select_table = $table;
echo $this->select_table;
}
public function select_col($col) {
$this->select_col = $col;
echo $this->select_col;
}
public function get_contents() {
$stmt = $this->connect->prepare('SELECT * FROM :table');
$stmt->bindParam(':table', $this->table , PDO::PARAM_STR);
$stmt->execute();
$result = $stmt->fetchAll();
while($row = $stmt->fetch()) {
print_r($row);
}
}
}
$conn = new dbConnect();
$conn->connect($dbUser,$dbPass);
$conn->select_table('users');
$conn->select_col('site_name');
$conn->get_contents();
?>
表不能绑定,请使用以下方法:
$this->connect->prepare('SELECT * FROM ' . $this->select_table);
还要注意,您使用的表中应该使用select_table