我有一个脚本,它正在生成一个基于用户选择的值的JSON数组。这些值以带有AJAX的JSON形式发送到PHP脚本,该脚本应该接收并处理这些值
可能出了什么问题?
JSON(已发送):
[{
"Pages":
{"name":" Page Name 1",
"id":"252456436636644"}
},
{
"Pages":{
"name":" Page Name 2",
"id":"345345435435232"
}
}]
Jquery:
var json_pages = JSON.stringify(publish);
$.ajax({
url: "post.php",
type: "post",
data: { PublishToPages: json_pages },
success: function(){},
error: function(){}
});
问题是我从PHP收到的JSON没有得到数据,
if($_POST['PublishToPages']) {
$json = $_POST['PublishToPages'];
$array = json_decode($json, true);
foreach($array as $item) {
$page_id = $item['Pages']['id'];
echo $page_id;
}
}
如果我像这样手动将JSON放入PHP脚本中,它会起作用,
if ($_POST['PublishToPages']) {
$json = '[{"Pages":{"name":" Page Name","id":"234545355345435"}},{"Pages":{"name":" Page Name 2","id":"345345435435435435"}}]';
$array = json_decode($json, true);
foreach($array as $item) {
$page_id = $item['Pages']['id'];
echo $page_id;
}
}
尝试使用这个:
if($_POST['PublishToPages']) {
$json = $_POST['PublishToPages'];
$items = array();
$array = json_decode($json, true);
foreach($array as $item) {
$page_id = $item['Pages']['id'];
$items[] = $page_id;
}
echo json_encode($items);
}
试试这个
$.ajax({
url: "post.php",
type: "post",
dataType:"json",
data: { PublishToPages: json_pages },
success: function(){},
error: function(){}
});
感谢您的输入!我使用var_dump找到了它,并意识到它是编码错误,所以添加了stripslashes();它成功了!:)
if ($_POST['PublishToPages']) {
$json = stripslashes($_POST['PublishToPages']);
$array = json_decode($json, true);
foreach($array as $item) {
$page_id = $item['Pages']['id'];
echo $page_id;
}
}