为什么这个极其简单的PHP代码不起作用?语法错误，意外的T_STRING - Why does this extremely simple PHP code not work? syntax error, unexpected T_STRING

Why does this extremely simple PHP code not work? syntax error, unexpected T_STRING

我刚刚报名参加树屋训练，我还有这个小挑战要完成。我无法让它发挥作用。如果变量设置为"vanilla"，我将获得成功的输出。然而，如果我使用"饼干面团"，那么我会出现语法错误，我想这可能是因为饼干和面团之间的空格？

 <?php 
        $flavor = cookie dough;
        echo "<p> Your favourite flavor is ";
        echo $flavor;
        echo ".</P>";
        if ($flavor == "cookie dough") {
            echo "<p> Yeah I like cookie dough aswell! </p>";
        }
    ?>

这里您忘记了""

$flavor = cookie dough;

应该是

$flavor = "cookie dough";
          ^            ^

用引号将$flavor变量值括起来。

<?php 
        $flavor = "cookie dough";
        echo "<p> Your favourite flavor is ";
        echo $flavor;
        echo ".</P>";
        if ($flavor == "cookie dough") {
            echo "<p> Yeah I like cookie dough aswell! </p>";
        }
    ?>

简单地说，

$flavor = cookie dough;

不是正确的代码，请用引号括起来。您可以在这里看到定义字符串的可能方法。

$flavor = cookie dough;

应该是

$flavor = 'cookie dough';或

$flavor = "cookie dough";

要定义字符串，应该使用"'"或'"'；

您忘记将cookie dough括在引号中：

$flavor = "cookie dough";