将城市名称从php传递到js(第2部分） - Pass city name from php to js (part 2)

Pass city name from php to js (part 2)

本文关键字：js 2部城市 php | 更新日期: 2023-09-27

续。基于所选州的马来西亚城市展示

城市数据json（$cityJsonObject）

Array ( [0] => stdClass Object ( [cityId] => c1 [cityName] => Kajang [cityStateId] 
=> s2 ) [1] => stdClass Object ( [cityId] => c2 [cityName] => Seputeh 
[cityStateId] => s1 ) [2] => stdClass Object ( [cityId] => c3 [cityName] => Shah 
Alam [cityStateId] => s2 ) [3] => stdClass Object ( [cityId] => c4 [cityName] => 
Klang [cityStateId] => s2 ) [4] => stdClass Object ( [cityId] => c5 [cityName] => 
Kepong [cityStateId] => s1 ))

代码（城市名称）

<?php
    for($i = 0; $i < count($cityJsonObject); $i++)
    {
        echo $cityJsonObject[$i]->cityName;
        //PASS VARIABLE TO JS
    }
?>
<script type="text/javascript">
    //GET VARIABLE FROM PHP AND DISPLAY CITY NAME
</script>

从上面的代码中，我可以得到以下内容：
```
Kajang 
Seputeh
Shah Alam
Klang
Kepong
```
我的问题是如何将上面的城市名称传递到一个变量中并传递给js？我该怎么办？

您可以使用json_encode并输出一个字符串，该字符串将被javascript 轻松解析

试试这个代码

<?php
    $array_to_js = array();
    for($i = 0; $i < count($cityJsonObject); $i++)
    {
        $array_to_js[] = $cityJsonObject[$i]->cityName;
    }
?>
<script type="text/javascript">
    //GET VARIABLE FROM PHP AND DISPLAY CITY NAME
    var js_array = <?php echo json_encode($array_to_js, JSON_HEX_QUOT) ?>;
</script>

<?php
echo '<script type="text/javascript">';
// your php code here maybe you can need json_encode(), I'm not sure I get what you mean.
echo json_encode($cityJsonObject);
echo '<script>';
?>