我有一个嵌套查询,当我在SQL server 2008 management studio中执行时,它运行得很好,它输出两个结果,但当我尝试在PHP中执行此操作时,我收到了一个错误,我认为这与PHP输出有关。
这里是SQL服务器中的查询,它可以工作,但我认为这是不对的:
select * from product_catalogue where catalogueid =(select catalogueid from products where productid = 1) (select * from products where productid = 1)
以下是PHP中的完整查询:
$query3 = "select * from product_catalogue where catalogueid =(select catalogueid from products where productid = '" . $productid . "') (select * from products where productid = '" . $productid . "')";
$result3 = sqlsrv_query( $conn, $query3, array(), array( "Scrollable" => SQLSRV_CURSOR_KEYSET ));
if( $result3 === false)
{
echo "Error in query preparation/execution.'n";
die( print_r( sqlsrv_errors(), true));
}
while( $obj = sqlsrv_fetch_object( $result3))
{
$prod_image = $obj->picturem;
$prod_id = $obj->catalogueID;
$prod_description = $obj->description;
$prod_price = $obj->product_price;
echo "<p>$prod_id" ;
echo "<br/>$prod_description" ;
echo "<br/>£$prod_price";
echo "<br/><br/><img src='$prod_image' width='200' height='400'/>";
echo "<br/><br/>";
}
运行此查询时我收到的错误是:
Error in query preparation/execution. Array ( [0] => Array ( [0] => 01000 [SQLSTATE] => 01000 [1] => 16954 [code] => 16954 [2] => [Microsoft][SQL Server Native Client 10.0][SQL Server]Executing SQL directly; no cursor. [message] => [Microsoft][SQL Server Native Client 10.0][SQL Server]Executing SQL directly; no cursor. ) [1] => Array ( [0] => 01S02 [SQLSTATE] => 01S02 [1] => 0 [code] => 0 [2] => [Microsoft][SQL Server Native Client 10.0]Cursor type changed [message] => [Microsoft][SQL Server Native Client 10.0]Cursor type changed ) )
我一直在研究嵌套查询,并翻阅PHP手册,试图了解更多关于如何输出结果的信息,我只是觉得因为它在SQL server management studio中工作,并不意味着语法是正确的。欢迎提出任何建议。
这实际上是两个完全独立的查询:
select * from product_catalogue where catalogueid =(select catalogueid from products where productid = 1)
和
(select * from products where productid = 1)
最简单的方法是将表连接到一个查询中——类似于:
select c.catalogueID,
c.product_name,
c.product_price,
c.description,
p.productID,
p.picturem,
p.picturew
from product p
join product_catalogue c on c.catalogueid = p.catalogueid
where p.productid = 1