我想以JSON格式将数据从iOS应用程序发送到PHP服务器。我在后台使用以下代码进行此操作：
$json = $_POST['json'];
$data = json_decode($json, TRUE);
$email = $data['email'];
$user_password = $data['password'];
我想在JSON变量中发送数据，这样我就可以接受中的数据JSON变量，然后逐个提取字段。
目前，我正在我的iOS应用程序中使用以下Swift代码进行此操作：
func login(){
let email:NSString = txtEmail.text!
let password:NSString = txtPassword.text!
let post:NSString = "username='(email)&password='(password)"
NSLog("PostData: %@",post);
let url:NSURL = NSURL(string:"http://example.com/test.php")!
let postData:NSData = post.dataUsingEncoding(NSASCIIStringEncoding)!
let postLength:NSString = String( postData.length )
let request:NSMutableURLRequest = NSMutableURLRequest(URL: url)
request.HTTPMethod = "POST"
request.HTTPBody = postData
request.setValue(postLength as String, forHTTPHeaderField: "Content-Length")
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
request.setValue("application/json", forHTTPHeaderField: "Accept")
var reponseError: NSError?
var response: NSURLResponse?
var urlData: NSData?
do {
urlData = try NSURLConnection.sendSynchronousRequest(request, returningResponse:&response)
} catch let error as NSError {
reponseError = error
urlData = nil
}
if ( urlData != nil ) {
let res = response as! NSHTTPURLResponse!;
NSLog("Response code: %ld", res.statusCode);
if (res.statusCode >= 200 && res.statusCode < 300)
{
let responseData:NSString = NSString(data:urlData!, encoding:NSUTF8StringEncoding)!
NSLog("Response ==> %@", responseData);
do {
let jsonData = try NSJSONSerialization.JSONObjectWithData(urlData!, options: NSJSONReadingOptions.MutableContainers) as? NSDictionary
let success:NSInteger = jsonData!.valueForKey("success") as! NSInteger
NSLog("Success: %ld", success);
} catch let error as NSError {
print(error.localizedDescription)
}
}
}
}
我想我必须发送一个JSON数组，但我不知道如何保存数组中的变量并将JSON数组发送到PHP服务器。有人有什么想法吗？
您可以通过创建字典数组来实现这一点：
var user_outer_arrary = [[String:Any]]()
var user_inner_array = [String: Any]();
var jsonData : Data? = nil
let user_data :[String:Any]=["email": email,"password": password];
user_outer_arrary.append(user_data);
user_inner_array=["json": user_outer_arrary]
然后转换为JSON:
do
{
jsonData = try JSONSerialization.data(withJSONObject: user_inner_array, options: JSONSerialization.WritingOptions.prettyPrinted)
}
catch
{
}