如何获取php到javascript变量的值是可能的


how to get the values from php to javascript variable is it possible

这是我的php脚本,我从中向ajax返回值,称之为

<?php
$questionid=$_GET['qid'];
$answer=$_GET['clickedvalue'];
$dbconnect=mysqli_connect('localhost','root','','quiz')or die("Error Connecting to database");
$query="select answer from question_answer where id=$questionid";
    $result=mysqli_query($dbconnect,$query);
    while($rows=mysqli_fetch_array($result))
    {
        $dbanswer=$rows['answer'];  
    }

    //array values which will be passed to json 
    $result=array('correct'=>'Correct Answer',
                   'incorrect'=>'Incorrect Answer'
                );
    if($dbanswer==$answer)
        {
            //json to be passed to next page with key value pair
            echo json_encode(array('display_msg'=>$result['correct'],'points'=>'positive'));    
        }
    else{
            echo json_encode(array('display_msg'=>$result['incorrect'],'points'=>'negative'));
        }   
?>

这是我的ajax代码

   $.ajax({
        url:'checkanswer.php',
        dataType:'json',
        data:{'clickedvalue':clickedvalue,'qid':qid},
        success:function(data){
        $this.find(".report").html(data.display_msg);
        $this.delay(1000).slideUp();
        }
        });

因此,我的问题是,我如何将从php传递的data.points对象的值作为json存储在javascript变量中,或者是否不可能直接存储在javascript变量中?如果是,如何存储?如果不是,如何获取值并存储在的某个位置?

只需在调用ajax之前添加一个临时变量一些类似的东西

var myTempVariable; //Temp JS variable to use somewhere else
$.ajax(
{
    url: 'checkanswer.php',
    dataType: 'json',
    data: 
    {
        'clickedvalue': clickedvalue,
        'qid': qid
    },
    success: function(data) {
        $this.find(".report").html(data.display_msg);
        $this.delay(1000).slideUp();
        myTempVariable = data; //assugn value to temp varaible
    }
});
ajax成功函数中的

var myVariable = data.points;

这可能有助于