如何将no-of-days数组转换为json格式 - How to convert no of days array into json format

How to convert no of days array into json format

我使用for循环创建了一个天数数组

$noOfDays=array();
for($i=1;$i<=31;$i++){
    if ($i == '1') {
        $noOfDays[$i]['Number']=$i;
        $noOfDays[$i]['Days']=$i.' Day';
    }else{
         $noOfDays[$i]['Number']=$i;
         $noOfDays[$i]['Days']=$i.' Days';
    }
}

然后将该数组转换为json

echo $noOfDaysjson= json_encode($noOfDays);

$noOfDaysjson返回json，如下所示：-

{**"1"**:{"Number":1,"Days":"1 Day"},**"2"**:{"Number":2,"Days":"2 Days"},**"3"**:{"Number":3,"Days":"3 Days"},**"4"**:{"Number":4,"Days":"4 Days"},"5":{"Number":5,"Days":"5 Days"},"6":{"Number":6,"Days":"6 Days"},"7":{"Number":7,"Days":"7 Days"},"8":{"Number":8,"Days":"8 Days"},"9":{"Number":9,"Days":"9 Days"},"10":{"Number":10,"Days":"10 Days"},"11":{"Number":11,"Days":"11 Days"},"12":{"Number":12,"Days":"12 Days"},"13":{"Number":13,"Days":"13 Days"},"14":{"Number":14,"Days":"14 Days"},"15":{"Number":15,"Days":"15 Days"},"16":{"Number":16,"Days":"16 Days"},"17":{"Number":17,"Days":"17 Days"},"18":{"Number":18,"Days":"18 Days"},"19":{"Number":19,"Days":"19 Days"},"20":{"Number":20,"Days":"20 Days"},"21":{"Number":21,"Days":"21 Days"},"22":{"Number":22,"Days":"22 Days"},"23":{"Number":23,"Days":"23 Days"},"24":{"Number":24,"Days":"24 Days"},"25":{"Number":25,"Days":"25 Days"},"26":{"Number":26,"Days":"26 Days"},"27":{"Number":27,"Days":"27 Days"},"28":{"Number":28,"Days":"28 Days"},"29":{"Number":29,"Days":"29 Days"},"30":{"Number":30,"Days":"30 Days"},"31":{"Number":31,"Days":"31 Days"}}

但我不想用json格式的用粗体显示1，2这样的编号

我如何获得json，如：-

'[{"Number":"1","Days":"1 Day"},{"Number":"2","Days":"2 Days"},{"Number":"3","Days":"3 Days"},{"Number":"4","Days":"4 Days"},....so on]';

这应该适用于您：

<?php
$noOfDays=array();
for($i=1;$i<=31;$i++){
    if ($i == '1') {
        $noOfDays[] = [
            'Number' => $i,
            'Days' => $i. ' Days' 
        ];
    }else{
        $noOfDays[] = [
            'Number' => $i,
            'Days' => $i. ' Day' 
        ];
    }
}
echo $noOfDaysjson= json_encode($noOfDays);

您所需的json表示您想要一个对象数组，如果这是您实际想要的，那么这将得到所需的结果。

<?php
$noOfDays=array();
for($i=1;$i<=31;$i++){
    $obj = new stdClass();
    $obj->Number = $i;
    if ($i == '1') {
        $obj->Days = $i. ' Day';
    }else{
        $obj->Days = $i. ' Days';
    }
    $noOfDays[] = $obj;
}
$noOfDaysjson = json_encode($noOfDays);
echo $noOfDaysjson;

最短和优化的方法：

$noOfDays = [];
for($i = 1; $i <= 31; $i++){
    $noOfDays[] = [
        'Number'=> $i,
        'Days' => $i . (($i == 1)? ' Day': ' Days' )
    ];
}

这里的所有答案都是正确的。。。

// in case you would like to change your array keys
define ('ARRAY_NUMBER', 'Number');
define ('ARRAY_DAYS',   'Days'  );
// i think it's more clean to avoid if else 31 times
$noOfDays = array();
$noOfDays[] = array(ARRAY_NUMBER    => 1,
                    ARRAY_DAYS      => '1 Day');
for ($i=2 ; $i<=31 ; $i++) {
    $noOfDays[] = array(ARRAY_NUMBER    => $i,
                        ARRAY_DAYS      => $i . ' Days');
}
var_dump(json_encode($noOfDays));

只需将数组设置为多维数组，即可尝试以下操作：

<?php
$noOfDays=array();
for($i=1;$i<=31;$i++){
    $noOfDays[] = [
                   'Number'=>$i,
                   'Days'=>$i. ($i == '1') ? ' Day' : ' Days'
                  ];
}
echo $noOfDaysjson= json_encode($noOfDays);